anonymous
  • anonymous
Find the y-intercept for the graph of the quadratic function.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
y + 4 = (x + 2)^2
anonymous
  • anonymous
ok, so the y intercept is when x = 0 right. so make x equal 0 and it becomes quite simple.
anonymous
  • anonymous
Hah its not simple to me. How would I make x equal to 0?

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anonymous
  • anonymous
replace x with the number 0. solve for y. that gives the (0,y) plug what you get for y into the second value of the ordered pair to get the ordered pair of the y intercept point.
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=y+%2B+4+%3D+%28x+%2B+2%29^2+
anonymous
  • anonymous
So its -4,
anonymous
  • anonymous
ok, we start with y + 4 = (x + 2)^2 // then we assume x = 0 so y + 4 = (0+2)^2 y+4 = (2)^2 y + 4 = 4 y = 4-4 y = 0 so the y intercept is at (0,0)
anonymous
  • anonymous
Got it

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