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gjhfdfg

  • one year ago

Find the y-intercept for the graph of the quadratic function.

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  1. gjhfdfg
    • one year ago
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    y + 4 = (x + 2)^2

  2. tomo
    • one year ago
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    ok, so the y intercept is when x = 0 right. so make x equal 0 and it becomes quite simple.

  3. gjhfdfg
    • one year ago
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    Hah its not simple to me. How would I make x equal to 0?

  4. tomo
    • one year ago
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    replace x with the number 0. solve for y. that gives the (0,y) plug what you get for y into the second value of the ordered pair to get the ordered pair of the y intercept point.

  5. tomo
    • one year ago
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    http://www.wolframalpha.com/input/?i=y+%2B+4+%3D+%28x+%2B+2%29^2+

  6. gjhfdfg
    • one year ago
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    So its -4,

  7. tomo
    • one year ago
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    ok, we start with y + 4 = (x + 2)^2 // then we assume x = 0 so y + 4 = (0+2)^2 y+4 = (2)^2 y + 4 = 4 y = 4-4 y = 0 so the y intercept is at (0,0)

  8. gjhfdfg
    • one year ago
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    Got it

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