At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

x^2 - 4x - 12 ≤ 0

Im lost

Don't be! Can you factor x²-4x-12=0?

x*x - 2*2*x-2*2*3
Like that?

2 & 12 being a & b?

Kinda,

That the product is 0 still? I dont know..

Agreed,

I dont get what your asking for, it would just be zero

No

Can you solve the equation x+2=0?

-2

wouldnt it be -6? instead of just 6

To find out what the sign (pos or neg) x²-4x-12 will get, just try a number between -2 and 6, e.g. x=0.
0² - 4*0 -12 = -12 <0, so negative there.
If you try in the other parts of the line you get this:

Wouldnt that make them infinitys?

If you put in very large numbers for x, the value of x^2 - 4x - 12 will also get very large, but we need not to worry about that, because we have to answer another question:
What values of x make x^2 - 4x - 12 smaller than zero?
The answer is visible in the image: between -2 and 6!
So if I color all solutions red, I get this:

Only one thing left: we have to write the solution (drawn in red) in interval notation...

How do you write all the numbers from -2 to 6 (including -2 and 6!) as an interval?

(-2,6)

That would exclude -2 and 6...