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rebecca1233 Group Title

BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = -1 x = 5 and y = 1 x = 5 and y = -1

  • one year ago
  • one year ago

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  1. rebecca1233 Group Title
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    @RadEn

    • one year ago
  2. rebecca1233 Group Title
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    @uri

    • one year ago
  3. RadEn Group Title
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    hint : diagonal = sqrt(l^2 + w^2) l=length, w=width

    • one year ago
  4. rebecca1233 Group Title
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    so wt do i do 5^2 + 12^3?

    • one year ago
  5. RadEn Group Title
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    5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that

    • one year ago
  6. rebecca1233 Group Title
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    so add 144 + 25 = 169

    • one year ago
  7. RadEn Group Title
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    sqrt(169) = ... ?

    • one year ago
  8. rebecca1233 Group Title
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    13

    • one year ago
  9. rebecca1233 Group Title
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    bt thats not an answer option

    • one year ago
  10. rebecca1233 Group Title
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    so wt do i do now

    • one year ago
  11. RadEn Group Title
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    yes, it just a start

    • one year ago
  12. RadEn Group Title
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    now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method

    • one year ago
  13. RadEn Group Title
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    or u can do trial error from ur options

    • one year ago
  14. rebecca1233 Group Title
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    i got it x= 5 y = 1

    • one year ago
  15. RadEn Group Title
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    yep, that's correct

    • one year ago
  16. rebecca1233 Group Title
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    thank you

    • one year ago
  17. RadEn Group Title
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    you're welcome

    • one year ago
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