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BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y.
x = 4 and y = 1
x = 4 and y = 1
x = 5 and y = 1
x = 5 and y = 1
 one year ago
 one year ago
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = 1 x = 5 and y = 1 x = 5 and y = 1
 one year ago
 one year ago

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RadEnBest ResponseYou've already chosen the best response.1
hint : diagonal = sqrt(l^2 + w^2) l=length, w=width
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
so wt do i do 5^2 + 12^3?
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
so add 144 + 25 = 169
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
bt thats not an answer option
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
or u can do trial error from ur options
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
i got it x= 5 y = 1
 one year ago
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