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 one year ago
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y.
x = 4 and y = 1
x = 4 and y = 1
x = 5 and y = 1
x = 5 and y = 1
 one year ago
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = 1 x = 5 and y = 1 x = 5 and y = 1

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RadEn
 one year ago
Best ResponseYou've already chosen the best response.1hint : diagonal = sqrt(l^2 + w^2) l=length, w=width

rebecca1233
 one year ago
Best ResponseYou've already chosen the best response.0so wt do i do 5^2 + 12^3?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.15^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that

rebecca1233
 one year ago
Best ResponseYou've already chosen the best response.0so add 144 + 25 = 169

rebecca1233
 one year ago
Best ResponseYou've already chosen the best response.0bt thats not an answer option

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1or u can do trial error from ur options

rebecca1233
 one year ago
Best ResponseYou've already chosen the best response.0i got it x= 5 y = 1
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