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rebecca1233

  • 3 years ago

BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = -1 x = 5 and y = 1 x = 5 and y = -1

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  1. rebecca1233
    • 3 years ago
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    @RadEn

  2. rebecca1233
    • 3 years ago
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    @uri

  3. RadEn
    • 3 years ago
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    hint : diagonal = sqrt(l^2 + w^2) l=length, w=width

  4. rebecca1233
    • 3 years ago
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    so wt do i do 5^2 + 12^3?

  5. RadEn
    • 3 years ago
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    5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that

  6. rebecca1233
    • 3 years ago
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    so add 144 + 25 = 169

  7. RadEn
    • 3 years ago
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    sqrt(169) = ... ?

  8. rebecca1233
    • 3 years ago
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    13

  9. rebecca1233
    • 3 years ago
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    bt thats not an answer option

  10. rebecca1233
    • 3 years ago
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    so wt do i do now

  11. RadEn
    • 3 years ago
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    yes, it just a start

  12. RadEn
    • 3 years ago
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    now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method

  13. RadEn
    • 3 years ago
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    or u can do trial error from ur options

  14. rebecca1233
    • 3 years ago
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    i got it x= 5 y = 1

  15. RadEn
    • 3 years ago
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    yep, that's correct

  16. rebecca1233
    • 3 years ago
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    thank you

  17. RadEn
    • 3 years ago
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    you're welcome

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