anonymous
  • anonymous
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = -1 x = 5 and y = 1 x = 5 and y = -1
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
RadEn
  • RadEn
hint : diagonal = sqrt(l^2 + w^2) l=length, w=width

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anonymous
  • anonymous
so wt do i do 5^2 + 12^3?
RadEn
  • RadEn
5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that
anonymous
  • anonymous
so add 144 + 25 = 169
RadEn
  • RadEn
sqrt(169) = ... ?
anonymous
  • anonymous
13
anonymous
  • anonymous
bt thats not an answer option
anonymous
  • anonymous
so wt do i do now
RadEn
  • RadEn
yes, it just a start
RadEn
  • RadEn
now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method
RadEn
  • RadEn
or u can do trial error from ur options
anonymous
  • anonymous
i got it x= 5 y = 1
RadEn
  • RadEn
yep, that's correct
anonymous
  • anonymous
thank you
RadEn
  • RadEn
you're welcome

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