rebecca1233
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y.
x = 4 and y = 1
x = 4 and y = -1
x = 5 and y = 1
x = 5 and y = -1
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rebecca1233
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@RadEn
rebecca1233
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@uri
RadEn
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hint : diagonal = sqrt(l^2 + w^2)
l=length, w=width
rebecca1233
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so wt do i do 5^2 + 12^3?
RadEn
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5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144
add of them, and take squareroot after that
rebecca1233
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so add 144 + 25
= 169
RadEn
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sqrt(169) = ... ?
rebecca1233
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13
rebecca1233
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bt thats not an answer option
rebecca1233
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so wt do i do now
RadEn
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yes, it just a start
RadEn
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now, the diagonal represnted by equations : d=2x + 3y and d=x+8y
and we knowed that the length of diagonals of rectangle is same, so
2x+3y=13 and
x+8y=13
solve for x and y by elimination or subt method
RadEn
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or u can do trial error from ur options
rebecca1233
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i got it
x= 5 y = 1
RadEn
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yep, that's correct
rebecca1233
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thank you
RadEn
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you're welcome