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rebecca1233
 2 years ago
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y.
x = 4 and y = 1
x = 4 and y = 1
x = 5 and y = 1
x = 5 and y = 1
rebecca1233
 2 years ago
BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y. x = 4 and y = 1 x = 4 and y = 1 x = 5 and y = 1 x = 5 and y = 1

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RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1hint : diagonal = sqrt(l^2 + w^2) l=length, w=width

rebecca1233
 2 years ago
Best ResponseYou've already chosen the best response.0so wt do i do 5^2 + 12^3?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.15^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144 add of them, and take squareroot after that

rebecca1233
 2 years ago
Best ResponseYou've already chosen the best response.0so add 144 + 25 = 169

rebecca1233
 2 years ago
Best ResponseYou've already chosen the best response.0bt thats not an answer option

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1now, the diagonal represnted by equations : d=2x + 3y and d=x+8y and we knowed that the length of diagonals of rectangle is same, so 2x+3y=13 and x+8y=13 solve for x and y by elimination or subt method

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1or u can do trial error from ur options

rebecca1233
 2 years ago
Best ResponseYou've already chosen the best response.0i got it x= 5 y = 1
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