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JenniferSmart1

  • 3 years ago

\[tan^{-1}0\] \[tan(...)=0\] that would be \[\frac \pi 2\] so \[tan^{-1}0=\frac \pi 2\]

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  1. JenniferSmart1
    • 3 years ago
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    @satellite73 Am I right?

  2. anonymous
    • 3 years ago
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    i mean yes!!

  3. anonymous
    • 3 years ago
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    sorry i am tired, i thought you wanted \(\tan^{-1}(1)\) you are right

  4. JenniferSmart1
    • 3 years ago
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    \[tan^{-1}\sqrt 3=\frac\pi 6\]

  5. anonymous
    • 3 years ago
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    now that one is wrong

  6. JenniferSmart1
    • 3 years ago
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    noooooo....

  7. anonymous
    • 3 years ago
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    \[\tan(\frac{\pi}{3})=\sqrt3\]

  8. JenniferSmart1
    • 3 years ago
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    oh it's \[\frac \pi 3\]

  9. anonymous
    • 3 years ago
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    so \[\tan^{-1}(\sqrt3)=\frac{\pi}{3}\]

  10. JenniferSmart1
    • 3 years ago
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    yeah tan is \[\frac yx\] yep makes sense haha

  11. anonymous
    • 3 years ago
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    yes it is

  12. JenniferSmart1
    • 3 years ago
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    awesome!

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