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JenniferSmart1

\[tan^{-1}0\] \[tan(...)=0\] that would be \[\frac \pi 2\] so \[tan^{-1}0=\frac \pi 2\]

  • one year ago
  • one year ago

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  1. JenniferSmart1
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    @satellite73 Am I right?

    • one year ago
  2. satellite73
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    i mean yes!!

    • one year ago
  3. satellite73
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    sorry i am tired, i thought you wanted \(\tan^{-1}(1)\) you are right

    • one year ago
  4. JenniferSmart1
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    \[tan^{-1}\sqrt 3=\frac\pi 6\]

    • one year ago
  5. satellite73
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    now that one is wrong

    • one year ago
  6. JenniferSmart1
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    noooooo....

    • one year ago
  7. satellite73
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    \[\tan(\frac{\pi}{3})=\sqrt3\]

    • one year ago
  8. JenniferSmart1
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    oh it's \[\frac \pi 3\]

    • one year ago
  9. satellite73
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    so \[\tan^{-1}(\sqrt3)=\frac{\pi}{3}\]

    • one year ago
  10. JenniferSmart1
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    yeah tan is \[\frac yx\] yep makes sense haha

    • one year ago
  11. satellite73
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    yes it is

    • one year ago
  12. JenniferSmart1
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    awesome!

    • one year ago
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