Jaweria
Help me Please!! y=cos^-1(sin x+5).
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Jaweria
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\[Y=\cos^{-1} (\sin x+5).\]
saifoo.khan
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And what do we have to do with this equation?
Jaweria
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We have to take derivative
saifoo.khan
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@satellite73
anonymous
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there is no such thing!
anonymous
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\[4\leq \sin(x)+5\leq 6\] and that is not in the domain of arccosine
Jaweria
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what is that?
saadi
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the derivative of vos^-1(x)
\[\Large \frac{d}{dx}(\cos^{-1}(x))=\frac{-1}{\sqrt{1-x^2}}\]
replace x with sinx+5 use chanin rule
\[\Large \frac{d}{dx}(\cos^-1{(\sin x+5)}=\frac{-1}{\sqrt{1-(\sin(x)+5)^2}}*\frac{d}{dx}(\sin(x+5))\]
Jaweria
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but what will be my answer for this equation? can you please help all the way till the answer?
saadi
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last time i provided answer was reported . try it i will guide you .
anonymous
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maybe it is
\[\cos^{-1}(\sin(x+5))\]
anonymous
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if so, then start with
\[\cos^{-1}(\sin(x+5))=\sqrt{1-(x+5)^2}\] and differentiate that