## Jaweria Group Title Help me Please!! y=cos^-1(sin x+5). one year ago one year ago

1. Jaweria

$Y=\cos^{-1} (\sin x+5).$

2. saifoo.khan

And what do we have to do with this equation?

3. Jaweria

We have to take derivative

4. saifoo.khan

@satellite73

5. satellite73

there is no such thing!

6. satellite73

$4\leq \sin(x)+5\leq 6$ and that is not in the domain of arccosine

7. Jaweria

what is that?

the derivative of vos^-1(x) $\Large \frac{d}{dx}(\cos^{-1}(x))=\frac{-1}{\sqrt{1-x^2}}$ replace x with sinx+5 use chanin rule $\Large \frac{d}{dx}(\cos^-1{(\sin x+5)}=\frac{-1}{\sqrt{1-(\sin(x)+5)^2}}*\frac{d}{dx}(\sin(x+5))$

9. Jaweria

last time i provided answer was reported . try it i will guide you .

11. satellite73

maybe it is $\cos^{-1}(\sin(x+5))$

12. satellite73

if so, then start with $\cos^{-1}(\sin(x+5))=\sqrt{1-(x+5)^2}$ and differentiate that