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Jaweria

  • 3 years ago

Help me Please!! y=cos^-1(sin x+5).

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  1. Jaweria
    • 3 years ago
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    \[Y=\cos^{-1} (\sin x+5).\]

  2. saifoo.khan
    • 3 years ago
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    And what do we have to do with this equation?

  3. Jaweria
    • 3 years ago
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    We have to take derivative

  4. saifoo.khan
    • 3 years ago
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    @satellite73

  5. anonymous
    • 3 years ago
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    there is no such thing!

  6. anonymous
    • 3 years ago
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    \[4\leq \sin(x)+5\leq 6\] and that is not in the domain of arccosine

  7. Jaweria
    • 3 years ago
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    what is that?

  8. saadi
    • 3 years ago
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    the derivative of vos^-1(x) \[\Large \frac{d}{dx}(\cos^{-1}(x))=\frac{-1}{\sqrt{1-x^2}}\] replace x with sinx+5 use chanin rule \[\Large \frac{d}{dx}(\cos^-1{(\sin x+5)}=\frac{-1}{\sqrt{1-(\sin(x)+5)^2}}*\frac{d}{dx}(\sin(x+5))\]

  9. Jaweria
    • 3 years ago
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    but what will be my answer for this equation? can you please help all the way till the answer?

  10. saadi
    • 3 years ago
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    last time i provided answer was reported . try it i will guide you .

  11. anonymous
    • 3 years ago
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    maybe it is \[\cos^{-1}(\sin(x+5))\]

  12. anonymous
    • 3 years ago
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    if so, then start with \[\cos^{-1}(\sin(x+5))=\sqrt{1-(x+5)^2}\] and differentiate that

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