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Help me Please!! y=cos^-1(sin x+5).

Calculus1
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\[Y=\cos^{-1} (\sin x+5).\]
And what do we have to do with this equation?
We have to take derivative

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Other answers:

there is no such thing!
\[4\leq \sin(x)+5\leq 6\] and that is not in the domain of arccosine
what is that?
the derivative of vos^-1(x) \[\Large \frac{d}{dx}(\cos^{-1}(x))=\frac{-1}{\sqrt{1-x^2}}\] replace x with sinx+5 use chanin rule \[\Large \frac{d}{dx}(\cos^-1{(\sin x+5)}=\frac{-1}{\sqrt{1-(\sin(x)+5)^2}}*\frac{d}{dx}(\sin(x+5))\]
but what will be my answer for this equation? can you please help all the way till the answer?
last time i provided answer was reported . try it i will guide you .
maybe it is \[\cos^{-1}(\sin(x+5))\]
if so, then start with \[\cos^{-1}(\sin(x+5))=\sqrt{1-(x+5)^2}\] and differentiate that

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