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Jaweria Group Title

Help me Please!! y=cos^-1(sin x+5).

  • one year ago
  • one year ago

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  1. Jaweria Group Title
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    \[Y=\cos^{-1} (\sin x+5).\]

    • one year ago
  2. saifoo.khan Group Title
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    And what do we have to do with this equation?

    • one year ago
  3. Jaweria Group Title
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    We have to take derivative

    • one year ago
  4. saifoo.khan Group Title
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    @satellite73

    • one year ago
  5. satellite73 Group Title
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    there is no such thing!

    • one year ago
  6. satellite73 Group Title
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    \[4\leq \sin(x)+5\leq 6\] and that is not in the domain of arccosine

    • one year ago
  7. Jaweria Group Title
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    what is that?

    • one year ago
  8. saadi Group Title
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    the derivative of vos^-1(x) \[\Large \frac{d}{dx}(\cos^{-1}(x))=\frac{-1}{\sqrt{1-x^2}}\] replace x with sinx+5 use chanin rule \[\Large \frac{d}{dx}(\cos^-1{(\sin x+5)}=\frac{-1}{\sqrt{1-(\sin(x)+5)^2}}*\frac{d}{dx}(\sin(x+5))\]

    • one year ago
  9. Jaweria Group Title
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    but what will be my answer for this equation? can you please help all the way till the answer?

    • one year ago
  10. saadi Group Title
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    last time i provided answer was reported . try it i will guide you .

    • one year ago
  11. satellite73 Group Title
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    maybe it is \[\cos^{-1}(\sin(x+5))\]

    • one year ago
  12. satellite73 Group Title
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    if so, then start with \[\cos^{-1}(\sin(x+5))=\sqrt{1-(x+5)^2}\] and differentiate that

    • one year ago
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