anonymous
  • anonymous
can someone help me with integrals? equation below
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
\[\int\limits_{}^{}tsec ^{2}2t\]
anonymous
  • anonymous
like your last problem, this is another integration by parts. How do we know? because sec^2 is ordinarily integrable but it's multiplied by t. Here, we let u = t, and dv = sec^2 (t). du = dt and v = tan(t) with this information, you should be able to solve.
anonymous
  • anonymous
lol i literally just figured it out right when you posted that lol ty though = )

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
one question though dv=sec^2 (2t) would be v=tan(2t) right?
anonymous
  • anonymous
one half that...chain rule!
anonymous
  • anonymous
so it would be 2tan(2t)?
anonymous
  • anonymous
= (
anonymous
  • anonymous
no no. 1/2 * tan2t
anonymous
  • anonymous
is that a law? = (
anonymous
  • anonymous
? well, the chain rule is not a "law" either you believe in it or you don't. If you don't then most mathematicians just won't work with you. :P
anonymous
  • anonymous
so wait everytime you have a trig sign with f(x) and you take the integral its that trig sign with f(x) multiplied by 1/f(x) ?
anonymous
  • anonymous
i'm sorry maybe i only remember the chain rule for derivatives... not integrals...
anonymous
  • anonymous
Well I mean it's a simple consequence of u substitution is what I mean. Suppose you wanted to integrate cos2t. you technically only know the formula for the integral of cost. But by being clever, you let u = 2t. du = 2dt. thus dt = (1/2)du. AGAIN I MUST REMIND YOU THESE ARE NOT FRACTIONS but they work out that way for these general cases. So (integral)cos2tdt = (integral) (1/2) cosu du. Why? because originally, we integrated with respect to dt. So we must change everything that is in terms of to to everything in terms of u. That is why this integral evaluates to 1/2 tan(2t)
anonymous
  • anonymous
ok thank you i'm sorry i suck at this = (
anonymous
  • anonymous
Hey no problem. It's always good to learn. We each have our own pace.
anonymous
  • anonymous
mine seems to be slower than a snails' = (

Looking for something else?

Not the answer you are looking for? Search for more explanations.