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OkayOkay
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Concentric Cylindrical Insulator and Conducting Shell: An infinitely long solid insulating cylinder of radius a = 4.5 cm is positioned with its symmetry axis along the zaxis as shown. The cylinder is uniformly charged with a charge density ρ = 49.0 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 13.6 cm, and outer radius c = 17.6 cm. The conducting shell has a linear charge density λ = 0.53μC/m. What is V(P) – V(R), the potential difference between points P and R? Point P is located at (x,y) = (50.0 cm, 50.0 cm).
 one year ago
 one year ago
OkayOkay Group Title
Concentric Cylindrical Insulator and Conducting Shell: An infinitely long solid insulating cylinder of radius a = 4.5 cm is positioned with its symmetry axis along the zaxis as shown. The cylinder is uniformly charged with a charge density ρ = 49.0 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 13.6 cm, and outer radius c = 17.6 cm. The conducting shell has a linear charge density λ = 0.53μC/m. What is V(P) – V(R), the potential difference between points P and R? Point P is located at (x,y) = (50.0 cm, 50.0 cm).
 one year ago
 one year ago

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dw:1360305874441:dw
 one year ago

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\[E=(roe)(r_{a})^{2}/(2*\epsilon*\pi*r _{d}) +(\lambda/(2\epsilon \pi r _{d}))\]
 one year ago

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I integrated from 0.5>0.7 but am not getting the right answer.
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
where is R?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
E is a constant.(I believe you can use gauss law to find the electric fieldthe one I got is different from yours though...take care of the volume and areas differently.) So, \(V=E\int d\vec l=E (\int dx + \int dy)\)
 one year ago

OkayOkay Group TitleBest ResponseYou've already chosen the best response.0
I did use gauss's law to find electric field. The electric field I posted was correct. I know because I already answered what the electric field is. what do you mean by constant? Where is E constant?
 one year ago

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\[\int\limits_{0.5}^{0.7}E dl\] with E being what I posted. I replaced rd with x and dl with dx and integrated but came up with the wrong answer no matter what sign I used.
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
E is not a variable of x, or z. isn't E just \((something)\hat j\) in the integral here? though...yeah, that's the correct boundaries. might there be a mistake in the answer?
 one year ago

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If he was just something then that would be saying he is constant along P to R but that is not the case. I appreciate your time, it seems no one else will help with this question.
 one year ago

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if E was just something then that would be saaying E is...****
 one year ago

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@TuringTest, do you think you might have some input?
 one year ago

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@Callisto
 one year ago
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