Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Concentric Cylindrical Insulator and Conducting Shell: An infinitely long solid insulating cylinder of radius a = 4.5 cm is positioned with its symmetry axis along the z-axis as shown. The cylinder is uniformly charged with a charge density ρ = 49.0 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 13.6 cm, and outer radius c = 17.6 cm. The conducting shell has a linear charge density λ = -0.53μC/m. What is V(P) – V(R), the potential difference between points P and R? Point P is located at (x,y) = (50.0 cm, 50.0 cm).

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1360305874441:dw|
\[E=(roe)(r_{a})^{2}/(2*\epsilon*\pi*r _{d}) +(\lambda/(2\epsilon \pi r _{d}))\]
I integrated from 0.5->0.7 but am not getting the right answer.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

where is R?
E is a constant.(I believe you can use gauss law to find the electric field--the one I got is different from yours though...take care of the volume and areas differently.) So, \(V=E\int d\vec l=E (\int dx + \int dy)\)
R (0,50)
I did use gauss's law to find electric field. The electric field I posted was correct. I know because I already answered what the electric field is. what do you mean by constant? Where is E constant?
\[-\int\limits_{0.5}^{0.7}E dl\] with E being what I posted. I replaced rd with x and dl with dx and integrated but came up with the wrong answer no matter what sign I used.
E is not a variable of x, or z. isn't E just \((something)\hat j\) in the integral here? though...yeah, that's the correct boundaries. might there be a mistake in the answer?
If he was just something then that would be saying he is constant along P to R but that is not the case. I appreciate your time, it seems no one else will help with this question.
*It
if E was just something then that would be saaying E is...****
@TuringTest, do you think you might have some input?

Not the answer you are looking for?

Search for more explanations.

Ask your own question