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anonymous
 3 years ago
how to find projection of conical surface lying along z axis on the xy plane ?????????????
anonymous
 3 years ago
how to find projection of conical surface lying along z axis on the xy plane ?????????????

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jtvatsim
 3 years ago
Best ResponseYou've already chosen the best response.0Think of shining a light down the z axis. If you have a cone, and shine a light on the very top, what kind of shadow will it cast? A circle. So the projection of a conical surface lying along the z axis is a circle on the xy plane (assuming you mean that the tip of the cone is on the z axis).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360306137675:dw

jtvatsim
 3 years ago
Best ResponseYou've already chosen the best response.0Yep, that will be a circle shadow :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i m okk.with circle but want to know that if dw:1360306291929:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360306412506:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@hartnn help..........

jtvatsim
 3 years ago
Best ResponseYou've already chosen the best response.0wow... not sure on that part... sorry :( anyone else got ideas?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0basically i m working on conversion of cartesian to spherical coordinates????????????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@saifoo.khan help plss

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Ashleyisakitty help plss...........

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0any idea @Ashleyisakitty

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 ,@Luis_Rivera ......pls help any1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, what is the dot product of?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360307330028:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I can't understand what it says do you mind typing it out?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THETA is a constant and represents equation of cone in spherical coordinates

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Are you asking for the projection of theta onto the x axis? There is no straightforward solution. in spherical polar, the conversion is x = (rho)*cos(theta)sin(phi). however, the fact that you have a unit vector for theta is confusing. The two are independent of each other. It's like comparing apples and oranges.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0For a "normal cone" the equation is typically theta = pi/4 if that helps

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0plsss...........w8 i m clearing what i intended to ask @khoala4pham

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360307890501:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360308115075:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0while finding A(thetha) i m getting dw:1360308301921:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Please use the equations. I have no idea what these symbols mean. If your question is what is the unit vector of theta dotted with that of x, then I have no idea. The conversion of x to theta or vice versa involves a Jacobian which is computationally tedious. They are of different coordinate systems!! The mapping of x,y,z to r,theta,phi is not straightforward. It's not simply asking what i dot j is or what j dot k is. Honestly, you are asking for help but what is the question asking? The projection of a cone onto the xy plane is any number of circles. They are inherently level curves of the cone.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0see i m asking if we have to convert cartesian to spherical coordinates we need to find the A(theta) FR THATwe need projection of cone first over over the xy plane ..then its projection along x and y axis to get dot product with unit vector along x and y axis respectively.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0see the case of finding A(r) it is simple the projection of line with distance r from origin on xy plane frst........that is dw:1360308936766:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Hero plsssssssssssssssssssss answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't even know what you are getting at. if you are looking for the conversion of cartesian to spherica;, x= rho*sin(phi)*cos(theta) y = rho*sin(phi)*sin(theta) z = rho*cos(phi) But the rest of your information is extremely lacking. This is some random cone in random space that can be projected in ANY way imaginable. If my light source is sufficiently far away, your projection is huge; if it's close, miniscule. There is no way to pinpoint one. You HAVE to specify at least a level curve or SOME CHARACTERISTIC of the cone. The equation theta = 1, theta = 2, theta = 3 are all cones. You are overcomplicating this problem if I am to understand correctly. Project it onto x and then onto y and take the vector sum. But you can't use spherical and cartesian at the same time! It's like calculating velocity in miles per hour and getting distance in kilometers without converting...it doesn't work.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but in my book answers are :dw:1360309534965:dw.................anyway thanks fr d help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'd dare say that is incorrect. for the first unit vector, by virtue of being a unit vector, it has to be <1,0,0>, <0,1,0>, <0,0,1>. Ax and Ay (if this is your notation) is <1,0,0> and <0,1,0>. One of those two dot products MUST equal zero.
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