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i'm really feeling like an idiot. i completely forgot how to do this. can someone refresh my memory?
 one year ago
 one year ago
i'm really feeling like an idiot. i completely forgot how to do this. can someone refresh my memory?
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.3
\[\large b^{n/a}=\sqrt[a]{b^n}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
Yeah, but because that's a negative, I think you should put a \(\large \sqrt[3]{216^{2}}\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
Remember this guy?\[\large a^{n} = \dfrac{1}{a^n}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
Yes, and now find the cube root of that thing.
 one year ago

chihiroasleafBest ResponseYou've already chosen the best response.0
use this \[a ^{n}=\frac{ 1 }{a ^{n} }\]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
\[216^{\frac{ 2 }{ 3 }} = \frac{ 1 }{216^{\frac{ 2 }{ 3 }} } = \frac{ 1 }{ \sqrt[3]{216^{2}}} \]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
Easier to think of it that way
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
here:\[\sqrt[3]{\dfrac{a}{b}} = \dfrac{\sqrt[3]{a}}{\sqrt[3]{b}}\]I know I am smashing you with too many properties :P
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
An easier way to think about it is to find the cube root of the numerator and the denominator separately
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{216^{\frac{ 2 }{ 3 }} } = \frac{ 1 }{ \left( 216^\frac{ 1 }{ 3 } \right)^2} = \frac{ 1 }{ \sqrt[3]{216^{2}}}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.3
To make some stuff simpler,\[\dfrac{1}{\sqrt[3]{(6^3)^2}} = \dfrac{1}{\sqrt[3]{(6^2)^3}}\]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
Probably easier to find the cube root of 216, THEN square it, than square 216, then find it's cube root... both methods yield the same answer.
 one year ago
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