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girleegurl

4/(x-2)+4/3=8/3

  • one year ago
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  1. jiji501
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    \[\frac{ 4 }{ x+2 } +\frac{ 4 }{ 3 } = \frac{ 8 }{ 3 }\]

    • one year ago
  2. DarthTony
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    *** \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\]

    • one year ago
  3. jiji501
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    Makes the denominators equal everywhere so: \[(\frac{ 4 }{ x-2 } x \frac{ 3 }{ 3 })+ (\frac{ 4 }{ 3 }x \frac{ x-2 }{ x-2 })= (\frac{ 8 }{ 3 }x \frac{ x-2 }{ x-2 })\]

    • one year ago
  4. jiji501
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    Yeah x-2, sorry.

    • one year ago
  5. girleegurl
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    is the answer 5

    • one year ago
  6. jiji501
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    12 + 4x-8 = 8x-16 20 = 4x x = 5

    • one year ago
  7. jiji501
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    Yes

    • one year ago
  8. nitz
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    4/(x-2)=8/3-4/3 4/(x-2)=4/3 1/(x-2)=4/3 x-2=3/4 x=(3/4)+2 x=11/2

    • one year ago
  9. girleegurl
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    thanq dear

    • one year ago
  10. jiji501
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    @nitz How'd you get from the second, to the third step?

    • one year ago
  11. DarthTony
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    4/(x-2)+4/3=8/3 \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\] \[\frac{4}{x-2}=\frac{8}{3}-\frac{4}{3}\] \[\frac{4}{x-2}=\frac{4}{3}\] \[x-2=3,x=5\]

    • one year ago
  12. DarthTony
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    4 is not 4 lol

    • one year ago
  13. nitz
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    sorry.....its 1/(x-2)=1/3 x-2=3 x=5

    • one year ago
  14. DarthTony
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    meant 4 is not 1 lol

    • one year ago
  15. girleegurl
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    thanq all

    • one year ago
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