girleegurl
4/(x2)+4/3=8/3



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jiji501
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\[\frac{ 4 }{ x+2 } +\frac{ 4 }{ 3 } = \frac{ 8 }{ 3 }\]

DarthTony
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*** \[\frac{4}{x2}+\frac{4}{3}=\frac{8}{3}\]

jiji501
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Makes the denominators equal everywhere so:
\[(\frac{ 4 }{ x2 } x \frac{ 3 }{ 3 })+ (\frac{ 4 }{ 3 }x \frac{ x2 }{ x2 })= (\frac{ 8 }{ 3 }x \frac{ x2 }{ x2 })\]

jiji501
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Yeah x2, sorry.

girleegurl
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is the answer 5

jiji501
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12 + 4x8 = 8x16
20 = 4x
x = 5

jiji501
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Yes

nitz
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4/(x2)=8/34/3
4/(x2)=4/3
1/(x2)=4/3
x2=3/4
x=(3/4)+2
x=11/2

girleegurl
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thanq dear

jiji501
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@nitz How'd you get from the second, to the third step?

DarthTony
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4/(x2)+4/3=8/3
\[\frac{4}{x2}+\frac{4}{3}=\frac{8}{3}\]
\[\frac{4}{x2}=\frac{8}{3}\frac{4}{3}\]
\[\frac{4}{x2}=\frac{4}{3}\]
\[x2=3,x=5\]

DarthTony
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4 is not 4
lol

nitz
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sorry.....its
1/(x2)=1/3
x2=3
x=5

DarthTony
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meant 4 is not 1
lol

girleegurl
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thanq all