anonymous
  • anonymous
4/(x-2)+4/3=8/3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\frac{ 4 }{ x+2 } +\frac{ 4 }{ 3 } = \frac{ 8 }{ 3 }\]
anonymous
  • anonymous
*** \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\]
anonymous
  • anonymous
Makes the denominators equal everywhere so: \[(\frac{ 4 }{ x-2 } x \frac{ 3 }{ 3 })+ (\frac{ 4 }{ 3 }x \frac{ x-2 }{ x-2 })= (\frac{ 8 }{ 3 }x \frac{ x-2 }{ x-2 })\]

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More answers

anonymous
  • anonymous
Yeah x-2, sorry.
anonymous
  • anonymous
is the answer 5
anonymous
  • anonymous
12 + 4x-8 = 8x-16 20 = 4x x = 5
anonymous
  • anonymous
Yes
anonymous
  • anonymous
4/(x-2)=8/3-4/3 4/(x-2)=4/3 1/(x-2)=4/3 x-2=3/4 x=(3/4)+2 x=11/2
anonymous
  • anonymous
thanq dear
anonymous
  • anonymous
@nitz How'd you get from the second, to the third step?
anonymous
  • anonymous
4/(x-2)+4/3=8/3 \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\] \[\frac{4}{x-2}=\frac{8}{3}-\frac{4}{3}\] \[\frac{4}{x-2}=\frac{4}{3}\] \[x-2=3,x=5\]
anonymous
  • anonymous
4 is not 4 lol
anonymous
  • anonymous
sorry.....its 1/(x-2)=1/3 x-2=3 x=5
anonymous
  • anonymous
meant 4 is not 1 lol
anonymous
  • anonymous
thanq all

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