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girleegurl

  • 3 years ago

4/(x-2)+4/3=8/3

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  1. jiji501
    • 3 years ago
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    \[\frac{ 4 }{ x+2 } +\frac{ 4 }{ 3 } = \frac{ 8 }{ 3 }\]

  2. DarthTony
    • 3 years ago
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    *** \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\]

  3. jiji501
    • 3 years ago
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    Makes the denominators equal everywhere so: \[(\frac{ 4 }{ x-2 } x \frac{ 3 }{ 3 })+ (\frac{ 4 }{ 3 }x \frac{ x-2 }{ x-2 })= (\frac{ 8 }{ 3 }x \frac{ x-2 }{ x-2 })\]

  4. jiji501
    • 3 years ago
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    Yeah x-2, sorry.

  5. girleegurl
    • 3 years ago
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    is the answer 5

  6. jiji501
    • 3 years ago
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    12 + 4x-8 = 8x-16 20 = 4x x = 5

  7. jiji501
    • 3 years ago
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    Yes

  8. nitz
    • 3 years ago
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    4/(x-2)=8/3-4/3 4/(x-2)=4/3 1/(x-2)=4/3 x-2=3/4 x=(3/4)+2 x=11/2

  9. girleegurl
    • 3 years ago
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    thanq dear

  10. jiji501
    • 3 years ago
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    @nitz How'd you get from the second, to the third step?

  11. DarthTony
    • 3 years ago
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    4/(x-2)+4/3=8/3 \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\] \[\frac{4}{x-2}=\frac{8}{3}-\frac{4}{3}\] \[\frac{4}{x-2}=\frac{4}{3}\] \[x-2=3,x=5\]

  12. DarthTony
    • 3 years ago
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    4 is not 4 lol

  13. nitz
    • 3 years ago
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    sorry.....its 1/(x-2)=1/3 x-2=3 x=5

  14. DarthTony
    • 3 years ago
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    meant 4 is not 1 lol

  15. girleegurl
    • 3 years ago
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    thanq all

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