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Yumira Group Title

Given the triangle below, what is cot∡B? Right triangle ABC with AC measuring 4 and BC measuring 7 square root of 33 over 4 7 times square root of 33 over 33 square root of 33 over 7 4 times square root of 33 over 33

  • one year ago
  • one year ago

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  1. dpaInc Group Title
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    this one?

    • one year ago
  2. Yumira Group Title
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    yess Imma Post the Picture (:

    • one year ago
  3. dpaInc Group Title
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    k

    • one year ago
  4. Yumira Group Title
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    • one year ago
  5. Yumira Group Title
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    No /:

    • one year ago
  6. dpaInc Group Title
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    do you know how to use the pythagorean theorem to find the missing side of the triangle?

    • one year ago
  7. Yumira Group Title
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    Lol Nope But my older brother thinks its square root of 33 over 7 is he right ?

    • one year ago
  8. dpaInc Group Title
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    no.... it's not \(\large \frac{\sqrt{33}}{7} \) do you know where the \(\large \sqrt{33} \) came from though?

    • one year ago
  9. Yumira Group Title
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    Sadly No /.\

    • one year ago
  10. Yumira Group Title
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    Nvm My Sister Explained It Thanks Though (:

    • one year ago
  11. dpaInc Group Title
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    ok... the sqrt(33) came from the pythagorean theorem: \(\large a^2+4^2=7^2 \) solving that you'll get \(\large a=\sqrt{33} \) but now the trigonometry part... cotangent is adjacent over opposite... ok.... nvmd..

    • one year ago
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