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Yumira

  • one year ago

Given the triangle below, what is cot∡B? Right triangle ABC with AC measuring 4 and BC measuring 7 square root of 33 over 4 7 times square root of 33 over 33 square root of 33 over 7 4 times square root of 33 over 33

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  1. dpaInc
    • one year ago
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    this one?

  2. Yumira
    • one year ago
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    yess Imma Post the Picture (:

  3. dpaInc
    • one year ago
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    k

  4. Yumira
    • one year ago
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  5. Yumira
    • one year ago
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    No /:

  6. dpaInc
    • one year ago
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    do you know how to use the pythagorean theorem to find the missing side of the triangle?

  7. Yumira
    • one year ago
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    Lol Nope But my older brother thinks its square root of 33 over 7 is he right ?

  8. dpaInc
    • one year ago
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    no.... it's not \(\large \frac{\sqrt{33}}{7} \) do you know where the \(\large \sqrt{33} \) came from though?

  9. Yumira
    • one year ago
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    Sadly No /.\

  10. Yumira
    • one year ago
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    Nvm My Sister Explained It Thanks Though (:

  11. dpaInc
    • one year ago
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    ok... the sqrt(33) came from the pythagorean theorem: \(\large a^2+4^2=7^2 \) solving that you'll get \(\large a=\sqrt{33} \) but now the trigonometry part... cotangent is adjacent over opposite... ok.... nvmd..

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