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## Yumira Group Title Given the triangle below, what is cot∡B? Right triangle ABC with AC measuring 4 and BC measuring 7 square root of 33 over 4 7 times square root of 33 over 33 square root of 33 over 7 4 times square root of 33 over 33 one year ago one year ago

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1. dpaInc Group Title

this one?

2. Yumira Group Title

yess Imma Post the Picture (:

3. dpaInc Group Title

k

4. Yumira Group Title

5. Yumira Group Title

No /:

6. dpaInc Group Title

do you know how to use the pythagorean theorem to find the missing side of the triangle?

7. Yumira Group Title

Lol Nope But my older brother thinks its square root of 33 over 7 is he right ?

8. dpaInc Group Title

no.... it's not $$\large \frac{\sqrt{33}}{7}$$ do you know where the $$\large \sqrt{33}$$ came from though?

9. Yumira Group Title

Sadly No /.\

10. Yumira Group Title

Nvm My Sister Explained It Thanks Though (:

11. dpaInc Group Title

ok... the sqrt(33) came from the pythagorean theorem: $$\large a^2+4^2=7^2$$ solving that you'll get $$\large a=\sqrt{33}$$ but now the trigonometry part... cotangent is adjacent over opposite... ok.... nvmd..