anonymous
  • anonymous
How many 3 digit positive integers N are there, such that N is a multiple of both 7 and 13?
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katieb
  • katieb
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anonymous
  • anonymous
So N= _ _ _ where the spaces denote each digit of N N=7*13*1=91 so we move on to the next N=7*13*2=182 Here you found one N, which is 182 Try the next N=7*13*3=273 You found another N, and so on
anonymous
  • anonymous
thanxx
anonymous
  • anonymous
70 x 13= 910 only one for" just "

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anonymous
  • anonymous
Welcome :-)

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