Here's the question you clicked on:
agarwal.khushi.77
How many 3 digit positive integers N are there, such that N is a multiple of both 7 and 13?
So N= _ _ _ where the spaces denote each digit of N N=7*13*1=91 so we move on to the next N=7*13*2=182 Here you found one N, which is 182 Try the next N=7*13*3=273 You found another N, and so on
70 x 13= 910 only one for" just "