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Cutiepo0

  • 3 years ago

What is the shortest air column, closed at one end, that will resonate at a frequency of 440 Hz when the speed of sound is 344 m/s? I tried using the wavelength= v/f formula, but I keep getting the wrong answer...

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  1. JamesJ
    • 3 years ago
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    well you can calculate the wavelength. But how does that wavelength relate to the column of air?

  2. JamesJ
    • 3 years ago
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    ...and it depends if it is open or closed. Yours is closed. This might help you: http://hyperphysics.phy-astr.gsu.edu/hbase/waves/opecol.html

  3. Cutiepo0
    • 3 years ago
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    I still don't really know what to do :( I don't know how the length of the column relates to anything

  4. Cutiepo0
    • 3 years ago
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    SO because the wavelength is .8, and in a closed cylinder, the length is 1/4 the wavelength, the answer is .2?

  5. luthier93
    • 3 years ago
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    Wavelength is v/4L for closed tube. Solve that for L to find length.

  6. JamesJ
    • 3 years ago
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    The wave doesn't oscillate at the closed end; it can't. That's why there's a node at that end. At the open end, that's the natural place for an anti-node. So if you drew out one entire wave form 0 to max to 0 to min to 0, you can see that that first anti-node is at the max, and that is 1/4 of the total wave length. So, given f and v, you have solved for wavelength, lambda. Now the length of that tube is L = lambda/4.

  7. Cutiepo0
    • 3 years ago
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    Thank you :)

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