A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
a bag contains 9 blue marbles, 8 white marbles and 3 red marbles. Three marbles are selected from the bag. What is the probability they are all red? What is the probability that they are all the same colours?
 one year ago
a bag contains 9 blue marbles, 8 white marbles and 3 red marbles. Three marbles are selected from the bag. What is the probability they are all red? What is the probability that they are all the same colours?

This Question is Closed

tomo
 one year ago
Best ResponseYou've already chosen the best response.1P(3 reds) = C(3,3)/C(20,3)

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0how do u solve that please?

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0at first, the probability of selecting a red marble is \(\frac{3}{20}\), and then it is \(\frac{2}{19}\), then it's \(\frac{1}{18}\). multiply them all to get the probability of selecting all 3 red ones!

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0so multiply all three fractions?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1^ yes multiply all three together \[\frac{ 3 }{ 20 } \times \frac{ 2 }{ 19 } \times \frac{ 1 }{18 } = ???\]

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0to get answer part a?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1For probability that they're all the same colours, add up three separate probabilities  prob of getting three white, and prob of getting three blue, and prob of getting three red (which we just found)

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0@agent0smith and then do you add them together? i forgot how to do that part.

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Yeah i think you just add them together

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0that is the answer i just found for multiplying all three?? which answer does that belong to there are two questions, first one is: What is the probability they are all red? and the second question is : What is the probability that they are all the same colours?

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0the answer you just found was the reds... please read through the explanation agent0smith and I just provided

tomo
 one year ago
Best ResponseYou've already chosen the best response.1more help: https://www.khanacademy.org/math/trigonometry/prob_comb/basic_prob_precalc/v/simpleprobability

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0the first part of the question the answer that i got was 0.00087719298..

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0so for part a my answer would be 0.001 and for part b my answer would be 0.31

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Show us how you did part b, so someone can check it.

tomo
 one year ago
Best ResponseYou've already chosen the best response.1part b. this is how you do it. C(n,r) is a combination. P(all the same color) = [(C(3,1)*C(9,3)+C(2,1)*C(8,3)+C(1,1)*C(3,3)]/C(20,3) the idea is C(3,1) is choosing the first color. then you have to choose three from that color. I chose blue to start with C(9,3). then you have C(2,1) which is because you have removed one color from the possible colors. then you have to choose 3 from that color. I chose white C(8,3). then you only have one color left C(1,1). this color must be red C(3,3). Then you divide by all possible combinations C(20,3). done.

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1@tomo are you sure that's correct? Because you'll end up with different probabilities depending on the order you enter them... eg if you choose white first instead of blue.

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1And a 32% chance of getting all three the same colour seems kinda high. The probability of JUST pulling out one blue from the bag is only 9/20 = 45%. Chance of getting three blues = 7.4%, chance of getting three reds = 0.09%, chance of getting three white = 4.91% Also note that my method and yours get the same probability IF you remove the C(3,1), C(2,1) and C(1,1) from your equation. my method on the left, yours on the right: \[\frac{ (3 \times 2 \times 1) + (9 \times 8 \times 7) + (8 \times 7 \times 6) }{ 20 \times 19 \times 18 } = \frac{ C(9,3) + C(8,3) +C(3,3) }{ C(20,3) }\]

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1They simplify to \[\frac{ 846 }{ 6840 } = \frac{ 141 }{ 1140 }\] So the prob. of picking three the same colour = 0.124 = 12.4%
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.