A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0f(x)= \[\frac{ x }{ x^2 +1 }\]

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1solve x^2 + 1 = 0 for x

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1tell me what you get

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0Would it just be x^2 = 1 ?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1good so far, what's next?

k.rajabhishek
 2 years ago
Best ResponseYou've already chosen the best response.0there will be no vertical asymptote

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm, Im not sure? Do I replace the variable with 1?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1take the square root of both sides x = sqrt(1) or x = sqrt(1) but there's a problem, you can't take the square root of 1 and get a real number

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1so x^2 + 1 = 0 has no real solutions

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1leading to the fact that \[\Large \frac{ x }{ x^2 +1 }\] has no vertical asymptotes

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0Ah, ok. Thank you.! Just out of curiosity, what happened to the x on top of the fraction?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1the numerator doesn't play any role in finding the vertical asymptotes unless you can make it cancel with something in the denominator

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1if you had something like x  x^2+x the fraction would simplify to 1 ________ x + 1 and this would be a case where the numerator plays a role

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0So basically the numerator was pointless in this equation?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1the basic thing is to simplify as much as possible (which couldn't be done in this case) then look at the denominator only

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0Got it, thank you again.!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.