Here's the question you clicked on:
Kagome_gurl8
Graph the relation and its inverse. Use open circles to graph the points of the inverse. x –10 –8 –2 7 y 5 3 –8 –4
to find the inverse switch x and y. I am not sure what your equations are here though, could you enter them using the equation editor?
A relation and its inverse when graphed has a special property: the points are symmetric across the line y=x. You can automatically eliminate the 3rd and 4th graphs because the third is symmetric across y axis and the 4th is symmetric across the x axis. Thus, it leaves graphs 1 and 2. It can be easily checked with the point (-10,5). Only in graph 2 does (-10,5) and (5,-10) appear.