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AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
From a hilltop to the west of Willy, Oompa Loompas launch gum balls out of slingshots toward his canoe. These gum balls travel in a linear path, dropping 3.2 meters as they travel eastward 15.3 meters to strike the canoe. 1. What's the distance from the Oompa Loompas to the canoe? 2. What is the angle, measured from the horizon, that the Oompa Loompas are firing from? 3. Is it possible for a sling sot propelled gumball to travel in a linear path? If not, what is the flaw in this logic?
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
If I have it drawn right, part a is the pyth. theorem.
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
dw:1360440654830:dw
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Maybe law of sines for part two?
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
I am not very good in English, but if your pic is correct, you found the distance right.
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Thanks so much! I think I drew it right. @Jonask what do you think?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
yes for 2dw:1360448299629:dw
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Awesome. Could I take the arctan?
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Whoops, no. I ment the law of sines.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
\(\theta\) on the @Jonask 's pic is not measured from the horizon.
 one year ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
No matter which angle you search, the law of sines is a ratio, it is mainly used to to find specific sides, but in such a rightangled triangle, as it seems (only judging by the picture  I haven't fully read the problem) you wouldn't want to use that law, more likely the regular trigonometric functions and solve for the angle.
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Where is the horizon?
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
I wonder if it is a right triangle, from part 4.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
dw:1360441416725:dw
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Oh boy.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
yes its like an angle of elevation @klimenkov dw:1360448668700:dw
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
yippee. So where do I go from here?
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
1st of all, is the pic 100% correct?
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
I really think the drawing is right. I really think the distance is right I do not know about part two, how to get the angle And I am unsure about the logic part 4.
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
*part 3
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Anybody?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
tan theta=3.2/15.3
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
not theta but alpha\[\tan \alpha=3.2/15.3\]
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
That is 0.00365.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
now to get alpha use arctan(0.00365)
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
That is 0.209129
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Thanks @Jonask
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Now for the next part///
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
first of all gravity wont allow the ball just to down at the same angle without pulling it towards the earth 2nd air resistance especially because the horizontal distance is too big compared to the vertical
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
I was thinking the same, had it wrote down. Wanted to verify. Thanks SOO much.
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
So what needed to be done to find the angle from the horizon?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
its that arctan 0.00365=0.209 degrees this also accounts for the balls imppsossible perpetual linear motion
 one year ago

AmTran_Bus Group TitleBest ResponseYou've already chosen the best response.1
Thanks and God Bless. Keep on living for Jesus.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
God Bless you too @AmTran_Bus
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
Looks correct.
 one year ago
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