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If I have it drawn right, part a is the pyth. theorem.

|dw:1360440654830:dw|

Maybe law of sines for part two?

I am not very good in English, but if your pic is correct, you found the distance right.

Thanks so much! I think I drew it right. @Jonask what do you think?

yes for 2|dw:1360448299629:dw|

Awesome. Could I take the arctan?

Whoops, no. I ment the law of sines.

Where is the horizon?

I wonder if it is a right triangle, from part 4.

|dw:1360441416725:dw|

Oh boy.

yes its like an angle of elevation @klimenkov |dw:1360448668700:dw|

yippee. So where do I go from here?

1st of all, is the pic 100% correct?

*part 3

Anybody?

tan theta=3.2/15.3

not theta but alpha\[\tan \alpha=3.2/15.3\]

That is 0.00365.

now to get alpha use arctan(0.00365)

That is 0.209129

Thanks @Jonask

Now for the next part///

I was thinking the same, had it wrote down. Wanted to verify. Thanks SOO much.

So what needed to be done to find the angle from the horizon?

Thanks and God Bless. Keep on living for Jesus.

God Bless you too @AmTran_Bus

Looks correct.