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ksaimouli

  • 3 years ago

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  1. ksaimouli
    • 3 years ago
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    \[\frac{ dy }{ dx}=3x+2y+1\]

  2. ksaimouli
    • 3 years ago
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    @Jonask

  3. Jonask
    • 3 years ago
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    is it differential equations wats the ???

  4. ksaimouli
    • 3 years ago
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    i should integrate both sides

  5. ksaimouli
    • 3 years ago
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    yes it is

  6. ksaimouli
    • 3 years ago
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    \[- \ln I6-yI=\frac{ x^3 }{ 3 }\]

  7. ksaimouli
    • 3 years ago
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    can u solve for y

  8. ksaimouli
    • 3 years ago
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    I= absolute value

  9. ksaimouli
    • 3 years ago
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    |dw:1360442409147:dw|

  10. Jonask
    • 3 years ago
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    \[\huge -\ln \left| 6-y \right|=\frac{x^3}{3}\] \[\huge 6-y=e^{-\frac{x^3}{3}+C}\] \[\huge y=\]

  11. ksaimouli
    • 3 years ago
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    okay thx i got it

  12. Jonask
    • 3 years ago
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    i never did this b4

  13. Jonask
    • 3 years ago
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    \[\huge y=6-e^{\frac{-x^3}{3}-C}\]by the way its -C

  14. ksaimouli
    • 3 years ago
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    but i dont understand how u got 6-y from -ln what happened to -

  15. Jonask
    • 3 years ago
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    if we divide both sides by - also there s no need to put abslute value on ln cos thats naturally defined for ln its always +

  16. Jonask
    • 3 years ago
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    when we divide by - we get ln 6-y=-x^3/3-C

  17. ksaimouli
    • 3 years ago
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    okay than you very much

  18. ksaimouli
    • 3 years ago
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    thank

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