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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ dy }{ dx}=3x+2y+1\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
is it differential equations wats the ???
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i should integrate both sides
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
yes it is
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[ \ln I6yI=\frac{ x^3 }{ 3 }\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
can u solve for y
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
I= absolute value
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360442409147:dw
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \ln \left 6y \right=\frac{x^3}{3}\] \[\huge 6y=e^{\frac{x^3}{3}+C}\] \[\huge y=\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay thx i got it
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
i never did this b4
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
\[\huge y=6e^{\frac{x^3}{3}C}\]by the way its C
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
but i dont understand how u got 6y from ln what happened to 
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
if we divide both sides by  also there s no need to put abslute value on ln cos thats naturally defined for ln its always +
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
when we divide by  we get ln 6y=x^3/3C
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay than you very much
 one year ago
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