ksaimouli
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ksaimouli
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\[\frac{ dy }{ dx}=3x+2y+1\]

ksaimouli
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@Jonask

Jonask
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is it differential equations wats the ???

ksaimouli
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i should integrate both sides

ksaimouli
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yes it is

ksaimouli
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\[ \ln I6yI=\frac{ x^3 }{ 3 }\]

ksaimouli
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can u solve for y

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I= absolute value

ksaimouli
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dw:1360442409147:dw

Jonask
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\[\huge \ln \left 6y \right=\frac{x^3}{3}\]
\[\huge 6y=e^{\frac{x^3}{3}+C}\]
\[\huge y=\]

ksaimouli
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okay thx i got it

Jonask
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i never did this b4

Jonask
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\[\huge y=6e^{\frac{x^3}{3}C}\]by the way its C

ksaimouli
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but i dont understand how u got 6y from ln what happened to 

Jonask
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if we divide both sides by 
also there s no need to put abslute value on ln cos thats naturally defined for ln
its always +

Jonask
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when we divide by  we get
ln 6y=x^3/3C

ksaimouli
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okay than you very much

ksaimouli
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thank