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AmTran_Bus
Velocity and acceleration mathematics question! Don't be scared to open... It looks long
A lemming marches off an ice berg, falling directly downward from a height of 12.40 ethers. 0.10 seconds later, he is 9.151 meters above the ocean below. 0.20 seconds this altitude is reduced to 5.804 meters, and at 0.30 seconds he as fallen to 2.359 meters above the ocean. 1. Via Matrix operations, develop a mathematical expression that represents this fall. 2. If the lemming failed to bring an umbrella, how many seconds into this fall would he impact the ocean? 3. If he did have an umbrella to break his fall, and he opened it 7.000 meters above the water, how much time would he have fallen freely prior to opening the umbrella? 4. What would his speed be the instant he opened his umbrella? 5. What is his acceleration due to gravity?
Why am i Tagged here ?
you gave me a medal.
I really don't know what to do especially via matrix operations. But I would take an expression \(\text{altitude = }at^3+bt^2+ct+d\), put the values for t (0, 0.1, 0.2, 0.3) and put the values for the altitude. And then i'd got a system of the linear equations. And solve it using matrix operations.
If you don't mind, could you show me what the equation would be? Like 12.40T3?
The first one will be \(12.4=a\cdot0^3+b\cdot0^2+c\cdot0+d\) Because at the moment \(t=0\) the lemming was at the height = 12.4 meters. Then you will have 4 equtions and 4 variables - a,b,c,d. Solve and find the law of the falling.
Oh my goodness. This one is ROUGH!
But that is for one, correct?
\(\text{altitude = }-4.9t^2-32t+12.4\)
Wow, thanks, how did you get that?
You should do this calculation by yourself. Be honest.