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anonymous
 3 years ago
Calculus: The region in the first quadrant bounded by the graphs of the equations y=(1/x), x=1, x=2, is revolved around the xaxis. Use the shell method to find the volume of the resulting solid.
anonymous
 3 years ago
Calculus: The region in the first quadrant bounded by the graphs of the equations y=(1/x), x=1, x=2, is revolved around the xaxis. Use the shell method to find the volume of the resulting solid.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need help finding h(y),,,, (Height)

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360447641218:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0m,,, ok, I know the bounds are [1,2], the radius is y.... now, the height i want to say (1/y)1????

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.0\(V=\pi\int \limits_1^2y^2dx\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The shell method uses the 2(pi) at the beginning. Can u explain how u got that answere?

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. You have to understand what integral means. This solid consists of many little cylinders like on the picdw:1360448107971:dw The volume of the cylinder is \(\pi R^2h\), on the pic \(R\) is \(y(x)\) and \(h\) is \(dx\). We want the whole solid, so we sum the volumes of this small cylinders and get the volume of the solid as an integral.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well,,, im still not getting the right answere. its suppoased to be (pi)/2....

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.0You have to calculate the integral I wrote correctly.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oops. I made a mistake xD Ok, got it thanks.
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