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I need help finding h(y),,,, (Height)

|dw:1360447641218:dw|

m,,, ok, I know the bounds are [1,2], the radius is y.... now, the height i want to say (1/y)-1????

\(V=\pi\int \limits_1^2y^2dx\)

The shell method uses the 2(pi) at the beginning. Can u explain how u got that answere?

well,,, im still not getting the right answere. its suppoased to be (pi)/2....

You have to calculate the integral I wrote correctly.

Oops. I made a mistake xD Ok, got it thanks.

You are welcome.