anonymous
  • anonymous
Calculus: The region in the first quadrant bounded by the graphs of the equations y=(1/x), x=1, x=2, is revolved around the x-axis. Use the shell method to find the volume of the resulting solid.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I need help finding h(y),,,, (Height)
klimenkov
  • klimenkov
|dw:1360447641218:dw|
anonymous
  • anonymous
m,,, ok, I know the bounds are [1,2], the radius is y.... now, the height i want to say (1/y)-1????

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klimenkov
  • klimenkov
\(V=\pi\int \limits_1^2y^2dx\)
anonymous
  • anonymous
The shell method uses the 2(pi) at the beginning. Can u explain how u got that answere?
klimenkov
  • klimenkov
Yes. You have to understand what integral means. This solid consists of many little cylinders like on the pic|dw:1360448107971:dw| The volume of the cylinder is \(\pi R^2h\), on the pic \(R\) is \(y(x)\) and \(h\) is \(dx\). We want the whole solid, so we sum the volumes of this small cylinders and get the volume of the solid as an integral.
anonymous
  • anonymous
well,,, im still not getting the right answere. its suppoased to be (pi)/2....
klimenkov
  • klimenkov
You have to calculate the integral I wrote correctly.
anonymous
  • anonymous
Oops. I made a mistake xD Ok, got it thanks.
klimenkov
  • klimenkov
You are welcome.

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