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artofspeed
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{a}f(ax)dx = \int\limits_{}^{}f(0)dx\int\limits_{}^{}f(a)dx = \int\limits_{a}^{0}f(x)dx\]

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.0You can check this on example. Try \(f(x)=x^2, a=1.\)

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.0It will more easy if you take \(f(x)=1\).

artofspeed
 one year ago
Best ResponseYou've already chosen the best response.0so it this whole expression correct?

sirm3d
 one year ago
Best ResponseYou've already chosen the best response.0only the first and last expressions can be equated.

artofspeed
 one year ago
Best ResponseYou've already chosen the best response.0actually, the first and last aren't equal. But what's wrong in the expression?

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{a}f(ax)dx \ne \int\limits_{}^{}f(0)dx\int\limits_{}^{}f(a)dx = \int\limits_{a}^{0}f(x)dx\]The primitive of \(f(ax)\) is \(\int f(ax)dx\) and not \(\int f(ax)dx\). You can check this by taking derivative. Now, I think you can answer your question by yourself.
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