leahwells
Find tan θ if sec θ =sqrt(37)/6 and sinθ< 0



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leahwells
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so what does that mean

lopus
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dw:1360450559681:dw

lopus
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cos0=7/sqrt(37)
you know sen0<0

lopus
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excusme 6

leahwells
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so the answer is six

lopus
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noooo \[\cos \theta= 6/\sqrt{37}\]

lopus
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\[\tan \theta=\frac{ \sin \theta }{ \frac{ 6 }{ \sqrt{37}} }\]

lopus
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\[\sin \theta=+\sqrt{1\cos ^{2}\theta}\]

lopus
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tan=0.695