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leahwells

  • 3 years ago

Find tan θ if sec θ =sqrt(37)/6 and sinθ< 0

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  1. leahwells
    • 3 years ago
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    so what does that mean

  2. lopus
    • 3 years ago
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    |dw:1360450559681:dw|

  3. lopus
    • 3 years ago
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    cos0=7/sqrt(37) you know sen0<0

  4. lopus
    • 3 years ago
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    excusme 6

  5. leahwells
    • 3 years ago
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    so the answer is six

  6. lopus
    • 3 years ago
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    noooo \[\cos \theta= 6/\sqrt{37}\]

  7. lopus
    • 3 years ago
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    \[\tan \theta=\frac{ \sin \theta }{ \frac{ 6 }{ \sqrt{37}} }\]

  8. lopus
    • 3 years ago
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    \[\sin \theta=+-\sqrt{1-\cos ^{2}\theta}\]

  9. lopus
    • 3 years ago
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    tan=0.695

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