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JenniferSmart1
Group Title
I'm having trouble cancelling out my units.
\[(N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\]
I've N left, but I should have N/C
 one year ago
 one year ago
JenniferSmart1 Group Title
I'm having trouble cancelling out my units. \[(N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\] I've N left, but I should have N/C
 one year ago
 one year ago

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jtvatsim Group TitleBest ResponseYou've already chosen the best response.0
\[N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\]
 one year ago

jtvatsim Group TitleBest ResponseYou've already chosen the best response.0
Just reposting the question :)
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
@phi
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
nevermind I think I see my mistake, C^2 doesn't cancel out C
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Very nice. You solved your own problem by yourself.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
But where is 2 in the numerator?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
2 in the numerator?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
m^2
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(\frac{C}{m^2}+\frac{C}{m^2}=\frac{2C}{m^2}\)
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
The m's are different, I can't add them. \[8.99\times10^9N\cdot m^2/C^2\left[\frac{(5\times10^{6}C)}{(0.11m)^2}+\frac{(5\times10^6C)}{(0.09m)^2}\right]\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
I just needed to cancel my units out to make sure I'm doing the calculations correctly, because the answer is supposed to be in N/C
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.2
\[\vec{E}=N/C\]
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Ah, i understood, that is ok.
 one year ago
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