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JenniferSmart1

I'm having trouble cancelling out my units. \[(N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\] I've N left, but I should have N/C

  • one year ago
  • one year ago

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  1. jtvatsim
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    \[N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\]

    • one year ago
  2. jtvatsim
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    Just reposting the question :)

    • one year ago
  3. JenniferSmart1
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    @phi

    • one year ago
  4. JenniferSmart1
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    nevermind I think I see my mistake, C^2 doesn't cancel out C

    • one year ago
  5. klimenkov
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    Very nice. You solved your own problem by yourself.

    • one year ago
  6. klimenkov
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    But where is 2 in the numerator?

    • one year ago
  7. JenniferSmart1
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    2 in the numerator?

    • one year ago
  8. JenniferSmart1
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    m^2

    • one year ago
  9. klimenkov
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    \(\frac{C}{m^2}+\frac{C}{m^2}=\frac{2C}{m^2}\)

    • one year ago
  10. JenniferSmart1
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    The m's are different, I can't add them. \[8.99\times10^9N\cdot m^2/C^2\left[\frac{(-5\times10^{-6}C)}{(0.11m)^2}+\frac{(5\times10^-6C)}{(0.09m)^2}\right]\]

    • one year ago
  11. JenniferSmart1
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    I just needed to cancel my units out to make sure I'm doing the calculations correctly, because the answer is supposed to be in N/C

    • one year ago
  12. JenniferSmart1
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    \[\vec{E}=N/C\]

    • one year ago
  13. klimenkov
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    Ah, i understood, that is ok.

    • one year ago
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