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## JenniferSmart1 2 years ago I'm having trouble cancelling out my units. $(N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]$ I've N left, but I should have N/C

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1. jtvatsim

$N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]$

2. jtvatsim

Just reposting the question :)

3. JenniferSmart1

@phi

4. JenniferSmart1

nevermind I think I see my mistake, C^2 doesn't cancel out C

5. klimenkov

Very nice. You solved your own problem by yourself.

6. klimenkov

But where is 2 in the numerator?

7. JenniferSmart1

2 in the numerator?

8. JenniferSmart1

m^2

9. klimenkov

$$\frac{C}{m^2}+\frac{C}{m^2}=\frac{2C}{m^2}$$

10. JenniferSmart1

The m's are different, I can't add them. $8.99\times10^9N\cdot m^2/C^2\left[\frac{(-5\times10^{-6}C)}{(0.11m)^2}+\frac{(5\times10^-6C)}{(0.09m)^2}\right]$

11. JenniferSmart1

I just needed to cancel my units out to make sure I'm doing the calculations correctly, because the answer is supposed to be in N/C

12. JenniferSmart1

$\vec{E}=N/C$

13. klimenkov

Ah, i understood, that is ok.

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