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JenniferSmart1

  • one year ago

I'm having trouble cancelling out my units. \[(N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\] I've N left, but I should have N/C

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  1. jtvatsim
    • one year ago
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    \[N \cdot \cancel{m^2}/\cancel{C^2)}\left[\frac{\cancel{C}}{\cancel{m}^2}+\frac{\cancel{C}}{\cancel{m}^2}\right]\]

  2. jtvatsim
    • one year ago
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    Just reposting the question :)

  3. JenniferSmart1
    • one year ago
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    @phi

  4. JenniferSmart1
    • one year ago
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    nevermind I think I see my mistake, C^2 doesn't cancel out C

  5. klimenkov
    • one year ago
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    Very nice. You solved your own problem by yourself.

  6. klimenkov
    • one year ago
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    But where is 2 in the numerator?

  7. JenniferSmart1
    • one year ago
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    2 in the numerator?

  8. JenniferSmart1
    • one year ago
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    m^2

  9. klimenkov
    • one year ago
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    \(\frac{C}{m^2}+\frac{C}{m^2}=\frac{2C}{m^2}\)

  10. JenniferSmart1
    • one year ago
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    The m's are different, I can't add them. \[8.99\times10^9N\cdot m^2/C^2\left[\frac{(-5\times10^{-6}C)}{(0.11m)^2}+\frac{(5\times10^-6C)}{(0.09m)^2}\right]\]

  11. JenniferSmart1
    • one year ago
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    I just needed to cancel my units out to make sure I'm doing the calculations correctly, because the answer is supposed to be in N/C

  12. JenniferSmart1
    • one year ago
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    \[\vec{E}=N/C\]

  13. klimenkov
    • one year ago
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    Ah, i understood, that is ok.

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