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ksaimouli

derivative

  • one year ago
  • one year ago

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  1. ksaimouli
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    |dw:1360450693081:dw|

    • one year ago
  2. ksaimouli
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    @phi

    • one year ago
  3. Jellopudin
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    Obamanation.

    • one year ago
  4. jtvatsim
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    that's \[\cos(\frac{3\pi}{2} + h)\] right?

    • one year ago
  5. ksaimouli
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    yes

    • one year ago
  6. ksaimouli
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    \[-\sin(\frac{ 3\pi }{ 2 }+h) \frac{ 3 \pi }{ }\]

    • one year ago
  7. ksaimouli
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    3 pi/2

    • one year ago
  8. jtvatsim
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    close, I don't think you should have a 3pi/2 though... since the derivative of 3pi/2 is 0.

    • one year ago
  9. ksaimouli
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    hmm whats the answer

    • one year ago
  10. jtvatsim
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    So assuming we are taking the derivative with respect to h, the deriviative of the inside by the chain rule is 1. So we just multiply -sin(3pi/2 + h) by 1 and get -sin(3pi/2 + h).

    • one year ago
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