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ksaimouli
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|dw:1360450693081:dw|
ksaimouli
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@phi
Jellopudin
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Obamanation.
jtvatsim
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that's \[\cos(\frac{3\pi}{2} + h)\] right?
ksaimouli
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yes
ksaimouli
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\[-\sin(\frac{ 3\pi }{ 2 }+h) \frac{ 3 \pi }{ }\]
ksaimouli
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3 pi/2
jtvatsim
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close, I don't think you should have a 3pi/2 though... since the derivative of 3pi/2 is 0.
ksaimouli
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hmm whats the answer
jtvatsim
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So assuming we are taking the derivative with respect to h, the deriviative of the inside by the chain rule is 1. So we just multiply
-sin(3pi/2 + h) by 1 and get -sin(3pi/2 + h).