- anonymous

how can u rewrite these logarithmic equations an equivalent exponent equation or the other way around m=loga x is equivalent to am=x1. log3 5=y,2. loga 7=-2then solvelog2x=-3,logx9=1/2

- katieb

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- anonymous

need help solving and rewriting

##### 1 Attachment

- anonymous

can u go over with this with me and help rewrite and solve

- anonymous

with attachment to help

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## More answers

- anonymous

Sorry for the delay, my paid gig had some one show up.
You've seen: \[\log_{a} b=x \rightarrow a^{x}=b\]

- anonymous

ok

- anonymous

\[\log_{3} 5=y\] What is the "base"?

- anonymous

5

- anonymous

No.
In exponential form \[3^y=5\] so the 3 is the base

- anonymous

\[base^{exponent}=answer\]

- anonymous

In log form
\[\log_{base}answer =exponent \]

- anonymous

OK?

- anonymous

ok

- anonymous

What is \[\log_{4} 16 = 2\] in exponential form?

- anonymous

4y=16,

- anonymous

right, 4^2 = 16

- anonymous

If we had to write
\[3^2=9\]
in log form, we'd write \[\log_{3}9=2 \]

- anonymous

OK?

- anonymous

ok

- anonymous

Your second problem is \[\log_{a}7=2 \]
What is the base here?

- anonymous

7y=-2

- anonymous

The base is a (it is that small sub scripted (a)

- anonymous

ok

- anonymous

The exponent is on the right side of the equal sign

- anonymous

-2

- anonymous

a7

- anonymous

Right, so try writing the a, the 7 and the -2 in exponential form

- anonymous

7a=-2

- anonymous

a is the base
-2 is the exponent and the 7 is the "answer"

- anonymous

\[a^{-2}=7\]

- anonymous

ok

- anonymous

so it would bea-2=7

- anonymous

How about \[\log_{a} 30 = 5\] What is that in exponential form?

- anonymous

Base is ___
Exponent is ____
and the answer is _____

- anonymous

a30=5

- anonymous

30

- anonymous

answer

- anonymous

right, 30 is the answer
a is the base
and 5 is the exponent

- anonymous

Try watching the first few minutes of this video
http://patrickjmt.com/properties-of-logarithms-part-1/

- anonymous

How did the video help?

- anonymous

ok

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