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how can u rewrite these logarithmic equations an equivalent exponent equation or the other way around m=loga x is equivalent to am=x1. log3 5=y,2. loga 7=-2then solvelog2x=-3,logx9=1/2

Mathematics
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need help solving and rewriting
can u go over with this with me and help rewrite and solve
with attachment to help

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Other answers:

Sorry for the delay, my paid gig had some one show up. You've seen: \[\log_{a} b=x \rightarrow a^{x}=b\]
ok
\[\log_{3} 5=y\] What is the "base"?
5
No. In exponential form \[3^y=5\] so the 3 is the base
\[base^{exponent}=answer\]
In log form \[\log_{base}answer =exponent \]
OK?
ok
What is \[\log_{4} 16 = 2\] in exponential form?
4y=16,
right, 4^2 = 16
If we had to write \[3^2=9\] in log form, we'd write \[\log_{3}9=2 \]
OK?
ok
Your second problem is \[\log_{a}7=2 \] What is the base here?
7y=-2
The base is a (it is that small sub scripted (a)
ok
The exponent is on the right side of the equal sign
-2
a7
Right, so try writing the a, the 7 and the -2 in exponential form
7a=-2
a is the base -2 is the exponent and the 7 is the "answer"
\[a^{-2}=7\]
ok
so it would bea-2=7
How about \[\log_{a} 30 = 5\] What is that in exponential form?
Base is ___ Exponent is ____ and the answer is _____
a30=5
30
answer
right, 30 is the answer a is the base and 5 is the exponent
Try watching the first few minutes of this video http://patrickjmt.com/properties-of-logarithms-part-1/
How did the video help?
ok

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