ToniRogers23
how can u rewrite these logarithmic equations an equivalent exponent equation or the other way around m=loga x is equivalent to am=x1. log3 5=y,2. loga 7=-2then solvelog2x=-3,logx9=1/2
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ToniRogers23
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need help solving and rewriting
ToniRogers23
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can u go over with this with me and help rewrite and solve
ToniRogers23
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with attachment to help
TransendentialPI
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Sorry for the delay, my paid gig had some one show up.
You've seen: \[\log_{a} b=x \rightarrow a^{x}=b\]
ToniRogers23
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ok
TransendentialPI
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\[\log_{3} 5=y\] What is the "base"?
ToniRogers23
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5
TransendentialPI
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No.
In exponential form \[3^y=5\] so the 3 is the base
TransendentialPI
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\[base^{exponent}=answer\]
TransendentialPI
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In log form
\[\log_{base}answer =exponent \]
ToniRogers23
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ok
TransendentialPI
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What is \[\log_{4} 16 = 2\] in exponential form?
ToniRogers23
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4y=16,
TransendentialPI
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right, 4^2 = 16
TransendentialPI
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If we had to write
\[3^2=9\]
in log form, we'd write \[\log_{3}9=2 \]
ToniRogers23
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ok
TransendentialPI
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Your second problem is \[\log_{a}7=2 \]
What is the base here?
ToniRogers23
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7y=-2
TransendentialPI
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The base is a (it is that small sub scripted (a)
ToniRogers23
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ok
TransendentialPI
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The exponent is on the right side of the equal sign
ToniRogers23
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-2
ToniRogers23
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a7
TransendentialPI
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Right, so try writing the a, the 7 and the -2 in exponential form
ToniRogers23
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7a=-2
TransendentialPI
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a is the base
-2 is the exponent and the 7 is the "answer"
TransendentialPI
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\[a^{-2}=7\]
ToniRogers23
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ok
ToniRogers23
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so it would bea-2=7
TransendentialPI
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How about \[\log_{a} 30 = 5\] What is that in exponential form?
TransendentialPI
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Base is ___
Exponent is ____
and the answer is _____
ToniRogers23
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a30=5
ToniRogers23
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30
ToniRogers23
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answer
TransendentialPI
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right, 30 is the answer
a is the base
and 5 is the exponent
TransendentialPI
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How did the video help?
ToniRogers23
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ok