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anonymous
 3 years ago
RHS HELP!!! (Reimann Sums) (Note that I have NOT learned about integrals yet) Here's the Q: I'm given a curve where 0<=x<=10, and there are 5 rectangles, so n=5. I calculated delta x to be 2. I'm really confused how to use these two formulas to find both the LHS and the RHS. I've typed the two formulas below, in my reply. Please help!! I AM REALLY CONFUSED! Thank you!
anonymous
 3 years ago
RHS HELP!!! (Reimann Sums) (Note that I have NOT learned about integrals yet) Here's the Q: I'm given a curve where 0<=x<=10, and there are 5 rectangles, so n=5. I calculated delta x to be 2. I'm really confused how to use these two formulas to find both the LHS and the RHS. I've typed the two formulas below, in my reply. Please help!! I AM REALLY CONFUSED! Thank you!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\ \huge \text {LHS:} \sum_{i=0}^{n1} f(x_i) Δ x \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\ \ \huge \text {RHS:} \sum_{i=1}^{n} f(x_i) Δ x \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well delta x = (ba)/n

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and what is your f(x)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what you're asking. I need your function value.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(\ \Huge \text{Oh, and: } x_i = a+iΔx \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you just started integrals you shouldve went over sigma notation im pretty sure, and you just expand it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This isn't helpful without the function. Otherwise the answer will be just theoretical stuff.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't have a function value... I'm only given a graph in my textbook and am told to find the lower estimate and an upper estimate.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And, we haven't even discussed what an integral is in class...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Could you give a description of what your graph is?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It looks something like:dw:1360464858577:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0My confusion is I'm not sure how to use the two summation equations....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And then use the values I know from the graph

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, that's better. Well you first need to partition the interval into 5 equal intervals. For the left Riemann: for your values x = 0,2,4,6,8, draw a vertical line that TOUCHES the graph of the function. This vertical line is the height of the rectangle that you are estimating the curve with. Each rectangle's width is 2. dw:1360465074815:dw For the right hand do the same except for now, use let the x values be x = 2,4,6,8,10 dw:1360465192357:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Note how the left hand Riemann is an underestimation of area while the right hand Riemann is an over estimation of area.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@khoala4pham How do I use the sigma equations? Where do they come into this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The sigma equations represent area. They mean that you sum up the areas of each individual rectangle. That is all that they mean. For the left hand Riemann, you take 2*(f(0) + f(2) + f(4) + f(6) + f(8)) For the right, 2*(f(2) + f(4) + f(6) + f(8) + f(10)) Why that though? Because for the RHR, the first rectangle has height f(0) and its width is 2. The second rectangle has height f(2) and width 2. So forth and so on.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How do you know to choose 0,2,4,6,8 and 2,4,6,8,10?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well your a is zero in this case. a is the place where your interval begins. From your equation of the left hand Riemann, you see that x_i = a + i*(deltax) i runs from 0 to n1. Well, n here is 5the domain is partitioned into 5 intervals. That means that i = 0,1,2,3,4. Consequently x will be x = 0 + 2(0), 0 + 2(1), 0+2(2),0+2(3),0+2(4) x = 0,2,4,6,8. The same applies to the right Riemann.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THAT MAKES SO MUCH MORE SENSE! THANK YOU, @khoala4pham! I was getting confused with the \(\ \Huge \sum \text{ notation!} \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The notation is highly ambiguous if you are not used to it. The x_i is a number. Deltax is also a number. You are summing numbers across indexes. How you found your index is obtained above.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you explain the RHS for "Well your a is zero in this case. a is the place where your interval begins. From your equation of the left hand Riemann, you see that x_i = a + i*(deltax) i runs from 0 to n1. Well, n here is 5the domain is partitioned into 5 intervals. That means that i = 0,1,2,3,4. Consequently x will be x = 0 + 2(0), 0 + 2(1), 0+2(2),0+2(3),0+2(4) x = 0,2,4,6,8. The same applies to the right Riemann." I dont really understand the RHS...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How you got the numbers 2,4,6,8,10

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If i runs from 1 to n, so that means i runs 1 to 5...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm getting like 2, 5 ...? x_1= (a=0) + (1)(delta x = 2) = 2 x_2 = (a=1) + (2)( delta x = 2) =5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@khoala4pham Why do you keep 0 constant? Consequently x will be x = 0 + 2(0), 0 + 2(1), 0+2(2),0+2(3),0+2(4) x = 0,2,4,6,8.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your equation of x_i = a + i*(delta x). a = 0 by default. a is the value that you start your interval with. if your interval were from (20,50) then a = 20. If your interval were (3,24), then a = 3. In your initial problem you told me that 0 <= x < = 10. Thus a = 0.
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