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HolyRoller.Best ResponseYou've already chosen the best response.0
i got this answer is it correct ?
 one year ago

youmeatsixBest ResponseYou've already chosen the best response.0
Are you in pre calc?
 one year ago

youmeatsixBest ResponseYou've already chosen the best response.0
Are you using sine and cosine?
 one year ago

youmeatsixBest ResponseYou've already chosen the best response.0
Okai I only know how to figure it out with that...sorry ._.
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
\[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
\[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]
 one year ago

DirectrixBest ResponseYou've already chosen the best response.1
@HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.
 one year ago

HolyRoller.Best ResponseYou've already chosen the best response.0
so was my answer correct?? @whpalmer4
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
As previously mentioned, one is, one is not.
 one year ago
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