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HolyRoller.
 2 years ago
Best ResponseYou've already chosen the best response.0i got this answer is it correct ?

youmeatsix
 2 years ago
Best ResponseYou've already chosen the best response.0Are you in pre calc?

youmeatsix
 2 years ago
Best ResponseYou've already chosen the best response.0Are you using sine and cosine?

youmeatsix
 2 years ago
Best ResponseYou've already chosen the best response.0Okai I only know how to figure it out with that...sorry ._.

geerky42
 2 years ago
Best ResponseYou've already chosen the best response.1\[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]

geerky42
 2 years ago
Best ResponseYou've already chosen the best response.1\[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]

Directrix
 2 years ago
Best ResponseYou've already chosen the best response.1@HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.

HolyRoller.
 2 years ago
Best ResponseYou've already chosen the best response.0so was my answer correct?? @whpalmer4

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0As previously mentioned, one is, one is not.
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