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HolyRoller.
 one year ago
Best ResponseYou've already chosen the best response.0i got this answer is it correct ?

youmeatsix
 one year ago
Best ResponseYou've already chosen the best response.0Are you in pre calc?

youmeatsix
 one year ago
Best ResponseYou've already chosen the best response.0Are you using sine and cosine?

youmeatsix
 one year ago
Best ResponseYou've already chosen the best response.0Okai I only know how to figure it out with that...sorry ._.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1@HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.

HolyRoller.
 one year ago
Best ResponseYou've already chosen the best response.0so was my answer correct?? @whpalmer4

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0As previously mentioned, one is, one is not.
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