anonymous
  • anonymous
What are the values of a & b ?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
i got this answer is it correct ?
anonymous
  • anonymous
Are you in pre calc?

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anonymous
  • anonymous
no geometry
anonymous
  • anonymous
Are you using sine and cosine?
anonymous
  • anonymous
no .....
anonymous
  • anonymous
Okai I only know how to figure it out with that...sorry ._.
anonymous
  • anonymous
its ok
geerky42
  • geerky42
\[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]
geerky42
  • geerky42
\[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]
Directrix
  • Directrix
@HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.
whpalmer4
  • whpalmer4
Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.
anonymous
  • anonymous
so was my answer correct?? @whpalmer4
whpalmer4
  • whpalmer4
As previously mentioned, one is, one is not.

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