## HolyRoller. 2 years ago What are the values of a & b ?

1. HolyRoller.

2. HolyRoller.

i got this answer is it correct ?

3. you-me-at-six

Are you in pre calc?

4. HolyRoller.

no geometry

5. you-me-at-six

Are you using sine and cosine?

6. HolyRoller.

no .....

7. you-me-at-six

Okai I only know how to figure it out with that...sorry ._.

8. HolyRoller.

its ok

9. geerky42

\[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]

10. geerky42

\[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]

11. Directrix

@HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.

12. whpalmer4

Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.

13. HolyRoller.

so was my answer correct?? @whpalmer4

14. whpalmer4

As previously mentioned, one is, one is not.