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HolyRoller.

What are the values of a & b ?

  • one year ago
  • one year ago

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  1. HolyRoller.
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    • one year ago
  2. HolyRoller.
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    i got this answer is it correct ?

    • one year ago
  3. you-me-at-six
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    Are you in pre calc?

    • one year ago
  4. HolyRoller.
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    no geometry

    • one year ago
  5. you-me-at-six
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    Are you using sine and cosine?

    • one year ago
  6. HolyRoller.
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    no .....

    • one year ago
  7. you-me-at-six
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    Okai I only know how to figure it out with that...sorry ._.

    • one year ago
  8. HolyRoller.
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    its ok

    • one year ago
  9. geerky42
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    \[\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}\]

    • one year ago
  10. geerky42
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    \[\dfrac{21}{20} = \dfrac{29}{b}\]\[\dfrac{21}{20} = \dfrac{20}{a}\]

    • one year ago
  11. Directrix
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    @HolyRoller. The value of b doesn't satisfy the converse of the Pythagorean Theorem. 20^2 +(400/21)^2 = (20/21)^2 FALSE So, I'm thinking b is not 20/21. For b, the lengths of the corresponding sides of the similar triangles is: 20/21 = b/29 which cranks out a value of b not equal to 20/21. I did get the same value of a that you attached using a/20 = 20/21.

    • one year ago
  12. whpalmer4
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    Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.

    • one year ago
  13. HolyRoller.
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    so was my answer correct?? @whpalmer4

    • one year ago
  14. whpalmer4
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    As previously mentioned, one is, one is not.

    • one year ago
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