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Sorry it is A - B - C - D - E
F - G - H - I

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Yes they are to act as the vertices of triangles.

Hmm i see, let me try that, i wasnt sure how to interpret it.

because if all three points were on the same line , you couldn't make a triangle

Yes that appears to work, 5C1 x 4C2 and 5C2 x 4C1 which adds to 70

\[^nC_k = \frac{n!}{k!(n-k)!}\]

i like to start with a picture usually

im not sure how to answer that,

sometimes rewriting the question into a simpler form can help