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geerky42
 2 years ago
Best ResponseYou've already chosen the best response.0Use USubstitution. Let u = 1+8sinx.

ammu123
 2 years ago
Best ResponseYou've already chosen the best response.0can u explain how to do it please.

sami21
 2 years ago
Best ResponseYou've already chosen the best response.1let t=1+8sin(x) then dt=8cos(x)dx 1/8dt=cos(x)dx integral becomes \[\Large \frac{1}{8}\int\limits_{}^{} \frac{1}{t}dt\] you may know that formula that \[\Large \int\limits_{}^{} \frac{1}{x}dx =\ln(x)+C\] use this to evaluate hte above integral then substitute back t=1+8sin(x)
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