A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Use USubstitution. Let u = 1+8sinx.

ammu123
 one year ago
Best ResponseYou've already chosen the best response.0can u explain how to do it please.

sami21
 one year ago
Best ResponseYou've already chosen the best response.1let t=1+8sin(x) then dt=8cos(x)dx 1/8dt=cos(x)dx integral becomes \[\Large \frac{1}{8}\int\limits_{}^{} \frac{1}{t}dt\] you may know that formula that \[\Large \int\limits_{}^{} \frac{1}{x}dx =\ln(x)+C\] use this to evaluate hte above integral then substitute back t=1+8sin(x)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.