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cluoBest ResponseYou've already chosen the best response.0
17/14^x is zero as x goes to infinity?
 one year ago

cluoBest ResponseYou've already chosen the best response.0
then 25arctan(x^5) is left right?
 one year ago

cluoBest ResponseYou've already chosen the best response.0
so can i get the solution without looking at the graph?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
Yeah, arctan(x^5) will approach the same limit as arctan(x)
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
@walters i don't think that's the correct function
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
It is this, right??\[\frac{ 17 }{ 14^x}+25*\arctan(x^5)\]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
lim x=> inf for arctan(x) is pi/2 if i recall correctly. Since we have 25arctan(x)... So 25pi/2.
 one year ago

waltersBest ResponseYou've already chosen the best response.1
ok it means it will bedw:1360488400036:dw
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
Hehe, still not the right function @walters
 one year ago

waltersBest ResponseYou've already chosen the best response.1
this means the answer is infinity sice the limit of the first part is infinity which will affect the second part of the function
 one year ago

cluoBest ResponseYou've already chosen the best response.0
how do you know the limit of arctan is pi/2?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
@walters this is the function \[\frac{ 17 }{ 14^x}+25*\arctan(x^5) \]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
lim of arctanx is pi/2 because... tanx has asymptotes at pi/2, and arctanx is its inverse. There might be more proof needed than that though...
 one year ago

cluoBest ResponseYou've already chosen the best response.0
i can see it is pi/2 on a graph when x goes to infinity but how to find it without a graph? or do you just memorize it?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
@cluo tan(x) is undefined for pi/2 radians. As x => pi/2, tanx approaches infinity. Therefore it's inverse, arctanx, is bounded between y= pi/2 and y= pi/2
 one year ago

waltersBest ResponseYou've already chosen the best response.1
ok i see is my mistake dw:1360488999424:dw thx @agent0smith
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
there you go :) you had the limit correct in your earlier post, 25pi/2, just had the function written incorrectly.
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
Make sense @cluo? The reason for the limit of arctanx as x => inf. is just due to arctanx being the inverse of tanx (tanx restricted to a domain pi/2 to pi/2)... since tanx is not onetoone, and thus doesn't have a valid inverse function w/o restriction.
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
I'll get a graph... do you remember much on inverse functions?
 one year ago

cluoBest ResponseYou've already chosen the best response.0
if i look at a graph then i see it, nope everything is hazy. how do you retain that information after years?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
haha, it took me a few mins to remember it, it wasn't instant. Maybe this will help: http://ocw.mit.edu/ans7870/18/18.013a/textbook/chapter01/images/tan_atan.gif See how the arctanx is *only* that part of tanx between x=pi/2 and pi/2?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
Plus it might be easier to remember that tan90 (degrees) is undefined.
 one year ago
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