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its the first one

17/14^x is zero as x goes to infinity?

then 25arctan(x^5) is left right?

so can i get the solution without looking at the graph?

|dw:1360488025343:dw|

Yeah, arctan(x^5) will approach the same limit as arctan(x)

@walters i don't think that's the correct function

It is this, right??\[\frac{ 17 }{ 14^x}+25*\arctan(x^5)\]

yes

lim x=> inf for arctan(x) is pi/2 if i recall correctly. Since we have 25arctan(x)... So 25pi/2.

ok it means it will be|dw:1360488400036:dw|

Hehe, still not the right function @walters

how do you know the limit of arctan is pi/2?

@walters this is the function \[\frac{ 17 }{ 14^x}+25*\arctan(x^5) \]

ok i see is my mistake
|dw:1360488999424:dw|
thx @agent0smith

kind of but not really

I'll get a graph... do you remember much on inverse functions?

Plus it might be easier to remember that tan90 (degrees) is undefined.