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Pologirl19

Simplify the sum

  • one year ago
  • one year ago

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  1. Pologirl19
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    \[\frac{ {w^2 +2w -24} }{w^2 +w -30 }+\frac{ 8 }{ w - 5 }\]

    • one year ago
  2. Pologirl19
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    I really need help!!

    • one year ago
  3. mjr632
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    \[\frac{a}{b}+\frac{c}{d} = \frac{a*d+b*c}{b*d}\] \[\frac{(w^2+2w-24)*(w-5)+(w^2+w-30)*8}{(w^2+w-30)*(w-5)}\] \[(w-5)(w^2+2w-24)=w^3+2w^2-24w-5w^2-10w+120\\ = w^3-3w^2-34w+120\\ \\ (w^2+w-30) * 8 = 8w^2+8w-240\\ (w^2+w-30)(w-5)=w^3+w^2-30w-5w^2+-5w+150 \\ = w^3-4w^2-35w+150\\ \] \[\frac{(w^3-3w^2-34w+120)+(8w^2+8w-240)}{w^3-4w^2-35w+150}\] \[\frac{w^3+5w^2-26w-120}{w^3-4w^2-35w+150} \]

    • one year ago
  4. mjr632
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    Is this what you needed?

    • one year ago
  5. Pologirl19
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    No that is none of the answers on mine

    • one year ago
  6. Pologirl19
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    \[\frac{ w-4 }{ w-5 } \]

    • one year ago
  7. Pologirl19
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    \[\frac{ w^2+2w-16 }{ w^2+w-30 }\]

    • one year ago
  8. Pologirl19
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    w+4 \[\frac{ w+4 }{w-5 }\]

    • one year ago
  9. Pologirl19
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    Those are my answers

    • one year ago
  10. Hero
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    Wow @mjr632...

    • one year ago
  11. Hero
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    \[\frac{(w + 6)(w - 4)}{(w + 6)(w - 5)}+\frac{ 8 }{ w - 5 }\]

    • one year ago
  12. Hero
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    \[\frac{\cancel{(w + 6)}(w - 4)}{\cancel{(w + 6)}(w - 5)}+\frac{ 8 }{ w - 5 }\]

    • one year ago
  13. Hero
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    \[\frac{w - 4}{w - 5}+\frac{ 8 }{ w - 5 }\]

    • one year ago
  14. Hero
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    \[\frac{w + 8 - 4}{w - 5}\] @Pologirl19 , I'm sure you can finish it from there

    • one year ago
  15. Pologirl19
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    Thank thank you so much in my book it made no sense

    • one year ago
  16. Hero
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    You're welcome

    • one year ago
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