Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

find the derivative of y with respect to x, t or theta. (a) e^7 - 10x Answer: -10e^7-10x (b) 8xe^x - 8e^x answer: 8xe^x (c) y= (x^2 -2x+4)e^x answer: (x^2+2)e^x (d) y= sin e^theta^4 answer: (-4theta^3 e^-theta^4) cos e^-theta^4 please show the steps. thank you

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
The first one is \[\Large e^{7-10x}\] right?
yes
The derivative of that isn't -10e^7-10x, so there has to be a typo somewhere

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

im not sure i think we have to use the u substitution method to find the answer.
oh wait, is the answer is \[\Large -10e^{7-10x}\] and not \[\Large -10e^{7}-10x\]
yea its the first one
this is why parenthesis are useful if 7-10x is in the exponent, then say e^(7-10x)
ok that makes more sense now
sorry about that
let u = 7 - 10x, which means du/dx = -10 this means \[\Large e^{7-10x}\] turns into \[\Large e^{u}\] then derive to get \[\Large e^{u}*\frac{du}{dx}\] \[\Large e^{u}(-10)\] \[\Large -10e^{u}\] \[\Large -10e^{7-10x}\]
I'm using the chain rule, which is If h(x) = f(g(x)), then h ' (x) = f ' (g(x)) * g ' (x)
ok i just need help with the other 3 as well
whats the derivative of 8xe^x
im not sure
use the product rule
tell me what you get
is it 8xe^x
no, but that's part of it though
Product Rule: if h(x) = f(x)*g(x), then h ' (x) = f ' (x) * g(x) + f(x) * g ' (x)

Not the answer you are looking for?

Search for more explanations.

Ask your own question