haleyking345
Solving Trig Equations:
a.) 2 sin x - csc x = 0
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haleyking345
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How do you solve?
Hoa
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csc x =1/sinx ----> 2sin x -1/sinx =0
(2sin^2 x -1 )/sinx =0 iff 2sin^2 x -1 =0
---> 2sin^2x =1 --->
sin^2x =1/2--->
sin x = +- 1/4 ---> x = +- arcsin (1/4)
haleyking345
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This is confusing. How did you get what you got?
haleyking345
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|dw:1360547428391:dw|
haleyking345
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Is that the answer?
haleyking345
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Ok, then how do you find what angle it is on the unit circle.