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Solving Trig Equations: a.) 2 sin x - csc x = 0

Mathematics
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How do you solve?
csc x =1/sinx ----> 2sin x -1/sinx =0 (2sin^2 x -1 )/sinx =0 iff 2sin^2 x -1 =0 ---> 2sin^2x =1 ---> sin^2x =1/2---> sin x = +- 1/4 ---> x = +- arcsin (1/4)
This is confusing. How did you get what you got?

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Is that the answer?
Ok, then how do you find what angle it is on the unit circle.

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