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haleyking345

  • 3 years ago

Solving Trig Equations: a.) 2 sin x - csc x = 0

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  1. haleyking345
    • 3 years ago
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    How do you solve?

  2. Hoa
    • 3 years ago
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    csc x =1/sinx ----> 2sin x -1/sinx =0 (2sin^2 x -1 )/sinx =0 iff 2sin^2 x -1 =0 ---> 2sin^2x =1 ---> sin^2x =1/2---> sin x = +- 1/4 ---> x = +- arcsin (1/4)

  3. haleyking345
    • 3 years ago
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    This is confusing. How did you get what you got?

  4. haleyking345
    • 3 years ago
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    |dw:1360547428391:dw|

  5. haleyking345
    • 3 years ago
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    Is that the answer?

  6. haleyking345
    • 3 years ago
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    Ok, then how do you find what angle it is on the unit circle.

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