Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

The astronomical object known as Crab Nebula is thhe remnant of an exploded star. The explosion was seen by the Chinese in 1054 C.E. However, the Crab Nebula is about 3500 LY distance from the Earth In what year did the star actually explode.

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
http://apod.nasa.gov/apod/image/0802/crabmosaic_hst_big.jpg
i dont understand why are we including the current year when it was viewed in 1054
hmm,

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

if the crab nebula is 3500 [lyr] away, then light traveling from the crab nebula will take 3500 [yr] to reach earth so to find the year that the light left the crab nebula just take away the travel time from the year it arrived at earth 1054 CE 1054-3500=
im here
2466
btw, im not sure where you got the distance to the crab nebula from because i thought it was 6500 lyr (not 3500 lyr)
my textbook says its about 3500 LY away
dont for get that the year will be before 0 CE so it will be ... BCE
(well i guess you can use that value if its in your book)
so what was the first answer you gave because that seemed to make a lot of sense if the speed of light is pretty fast
\[s=\frac{d}{t}\qquad\implies t=\frac ds\] \[d=3500 [\text{ly}]=3500\times c\times[\text {yr}]\]\[s=c\] \[t=\frac ds=\frac{3500\times c\times[\text {yr}]}{c}=3500 [\text {yr}]\] \[1054[\text{yr}]~C.E.-3500[\text{yr}]=-2446~C.E.=2446~B.C.E\]
Ok thank you for your time and explanation.
sorry about my first post[now deleted] ( i only just woke up)
its fine you've helped me understand with the formulas you've provided

Not the answer you are looking for?

Search for more explanations.

Ask your own question