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what is the integral of e^(senx) 4cosx dx ? how can i solve it?

Mathematics
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\[\int\limits_{}^{}e ^{sen x} 4\cos x dx\]
sen? You mean sec?
try \(u=\sin(x), du=\cos(x)dx\) and you get it in one step

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i got \[[e^{sen x} +c] [4 sen x + c]\] is that correct?
i meant "sin":
\(\int e^{\sin(x)}\cdot 4\cos(x)\;dx\) Following satellite73 suggestion u = sin(x) du = cos(x)dx This gives \(\int e^{u}\cdot 4\;du = 4\cdot e^{u} + C\) Substitute back to where we started. \(4\cdot e^{\sin(x)} + C\) Be careful, consistent, and confident.
thank you so much! but what happened with cos ?
It's all in there with the nature of the substitution. See the definition of du.
so in this case cos represents the derivative for sin in the formula , right?
That is where it came from. You can't just substitute a function. The nature of dx changes when you do that. Is English your first language? The answer to this question might help other folks understand where "sen(x)" came from.
haha yeah, uhmm but right now im studying in a spanish-speaking country, so sometimes (unconsciously) isay or write spanish :/ . thank you so!
No worries - as long as you don't mind freaking people out when you accidentally write the spanish versions of things. Good work!

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