hey guys, sal here would like some help with these piecewise graphs

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hey guys, sal here would like some help with these piecewise graphs

Mathematics
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http://vvcap.net/db/Ea8WobNvpKnowqaCZesR.htp
step one: find the domain of each piece, step two: find the equation that describes the interval on each domain step three: combine
ill give you a different example |dw:1360553796475:dw|

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|dw:1360554027098:dw| the domain for the first piece is 0≤x≤2 the equation for this interval is y=x the domain for the second piece is 2≤x the equation for the second piece is y=2
combining \[y=\begin{cases}x&0≤x≤2\\2&2≤x\end{cases}\]
makes sense?
yes!! a million times yes!! let me work it out! thank you so much, about to give up.
can you help me with number 1 on my link above? just to know im doing it right?
what have you got so far?
for the first one i got \[f(x) = \left\{ 3 ; 0 \le x \le 3\right\}\]
and \[\left\{ x ; 3\le x \le 6 \right\}\]
what did you get for the equation of the second interval , y=x? thats not right
how?
i mean y=-x+7 the slope is -1 and the y- intercept would be at y=7
how did you get that thou/
|dw:1360558315458:dw|
|dw:1360558377826:dw|
|dw:1360558456267:dw|
\[y=mx+b=-x+7\]
OHHHHHH
is that the way to do it thou? or is there some equation/
um, you could find the equation of the line using the Two-point formula, since you have at least two points
how would i got about doing that?
i thik thats what they want us to do.
the Two-point formula\[y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\]
do i get just any set of points?
so you could use the points \((x_1,y_1)=(3,4)\) \((x_2,y_2)=(6,1)\) but you could choose different points on the line and you should get the same answer
thank you!

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