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anonymous
 3 years ago
3sqrt(x)/9x. how do you break down?
anonymous
 3 years ago
3sqrt(x)/9x. how do you break down?

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UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{3\sqrt x}{9x}\] factorize the denominator use \[(a+b)(ab)=a^2ab+bab^2=a^2b^2\] cancel common factors

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i know that but how do you that for sqrt?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1use \(x=\sqrt x^2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0mmm so 3sqet(x)=(x^23^9)?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1your looking at the numerator (bottom bit of the fraction) you should be looking at the denominator ( the bottom bit of the fraction) \[9x=(\cdots)(\cdots)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.09x...... sqert(3)(x)??

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[9x=3^2\sqrt x^2=(\cdots)(\cdots)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(3sq\[\left( 3\sqrt{x} \right)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(3sq\[\left( 3\sqrt{x} \right)\](3sq\[\left( 3\sqrt{x} \right)\]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( 3\sqrt{x} \right)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\left( 3sqrt{x} \right) \left( 3sqrt{x} \right)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(3sqrt(x)) (3sqrt(x)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1not quite\[a^2b^2=(a+b)(ab)\] so\[9x=3^2\sqrt x^2=\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[9x=3^2\sqrt x^2=(3+\sqrt x)(3\sqrt x)\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1so\[\frac{3\sqrt x}{9x}=\frac{3\sqrt x}{(3+\sqrt x)(3{\sqrt x)}}\]\[\qquad\qquad =\frac{\cancel{3\sqrt x}}{(3+\sqrt x)\cancel{(3{\sqrt x)}}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what about x^3+64/x+4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got (x+4)(x^2+4x+16)/(x+4)?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1almost \[(a^3+b^3)=(a+b)(a^2ab+b^2)\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1once you have fixed the sign error, cancel the common factor

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you it was very helpful!!
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