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Dodo1 Group Title

3-sqrt(x)/9-x. how do you break down?

  • one year ago
  • one year ago

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  1. UnkleRhaukus Group Title
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    \[\frac{3-\sqrt x}{9-x}\] factorize the denominator use \[(a+b)(a-b)=a^2-ab+ba-b^2=a^2-b^2\] cancel common factors

    • one year ago
  2. Dodo1 Group Title
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    yes i know that but how do you that for sqrt?

    • one year ago
  3. UnkleRhaukus Group Title
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    use \(x=\sqrt x^2\)

    • one year ago
  4. Dodo1 Group Title
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    mmm so 3-sqet(x)=(x^2-3^9)?

    • one year ago
  5. UnkleRhaukus Group Title
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    your looking at the numerator (bottom bit of the fraction) you should be looking at the denominator ( the bottom bit of the fraction) \[9-x=(\cdots)(\cdots)\]

    • one year ago
  6. Dodo1 Group Title
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    9-x...... sqert(3)-(x)??

    • one year ago
  7. UnkleRhaukus Group Title
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    \[9-x=3^2-\sqrt x^2=(\cdots)(\cdots)\]

    • one year ago
  8. Dodo1 Group Title
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    (3-sq\[\left( 3-\sqrt{x} \right)\]

    • one year ago
  9. Dodo1 Group Title
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    (3-sq\[\left( 3-\sqrt{x} \right)\](3-sq\[\left( 3-\sqrt{x} \right)\]?

    • one year ago
  10. Dodo1 Group Title
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    \[\left( 3-\sqrt{x} \right)\]

    • one year ago
  11. Dodo1 Group Title
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    \left( 3-sqrt{x} \right) \left( 3-sqrt{x} \right)

    • one year ago
  12. Dodo1 Group Title
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    (3-sqrt(x)) (3-sqrt(x)

    • one year ago
  13. UnkleRhaukus Group Title
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    not quite\[a^2-b^2=(a+b)(a-b)\] so\[9-x=3^2-\sqrt x^2=\]

    • one year ago
  14. Dodo1 Group Title
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    3-sqrt(x)?

    • one year ago
  15. Dodo1 Group Title
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    hope its right

    • one year ago
  16. UnkleRhaukus Group Title
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    \[9-x=3^2-\sqrt x^2=(3+\sqrt x)(3-\sqrt x)\]

    • one year ago
  17. UnkleRhaukus Group Title
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    so\[\frac{3-\sqrt x}{9-x}=\frac{3-\sqrt x}{(3+\sqrt x)(3-{\sqrt x)}}\]\[\qquad\qquad =\frac{\cancel{3-\sqrt x}}{(3+\sqrt x)\cancel{(3-{\sqrt x)}}}\]

    • one year ago
  18. Dodo1 Group Title
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    Thanks!!

    • one year ago
  19. Dodo1 Group Title
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    what about x^3+64/x+4

    • one year ago
  20. Dodo1 Group Title
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    I got (x+4)(x^2+4x+16)/(x+4)?

    • one year ago
  21. UnkleRhaukus Group Title
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    almost \[(a^3+b^3)=(a+b)(a^2-ab+b^2)\]

    • one year ago
  22. UnkleRhaukus Group Title
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    once you have fixed the sign error, cancel the common factor

    • one year ago
  23. Dodo1 Group Title
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    Thank you it was very helpful!!

    • one year ago
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