Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

PrecalcIsNotMyFriend

  • 3 years ago

Identities- Ugh! 1÷cscθ−cotθ=1+cosθ÷sinθ

  • This Question is Open
  1. Tushara
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    r u missing any brackets?

  2. ZeHanz
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    It should be:\[\frac{ 1 }{ \csc \theta - \cot \theta }=\frac{ 1+\cos \theta }{ \sin \theta }\]Let's begin at the left hand side:\[\frac{ 1 }{ \csc \theta - \cot \theta }=\frac{ 1 }{ \frac{ 1 }{ \sin \theta }-\frac{ \cos \theta }{ \sin \theta } }=\frac{ 1 }{ \frac{ 1-\cos \theta }{ \sin \theta } }=\frac{ \sin \theta }{ 1- \cos \theta }\]This looks much better, although it is not quite the right hand side yet... Hint: multiply numerator and denominator of the last fraction with (1+cosθ)/(1+cosθ):\[\frac{ \sin θ }{ 1-\cos θ } \cdot \frac{ 1+\cos θ }{ 1+\cos θ }= ...\]After just a few small steps, you'll have got to the right hand side of the identity!

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy