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heartylove
Find the exact value of sin((cos^-1)(5/13))
draw a right triangle and label the sides according to what's given... let \(\large \theta=cos^{-1}(\frac{5}{13}) \) now, \(\large \theta=cos^{-1}(\frac{5}{13}) \) means \(\large cos\theta=\frac{5}{13} \) so you can draw the right triangle along with the angle theta...|dw:1360580027671:dw|
since the problem is \(\large sin(cos^{-1}\frac{5}{13})=sin(\theta)=??? \) you can see that you need to find the side opposite theta to find sin(theta).... just use pythagorean theorem...