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koli123able

  • 3 years ago

What is the nth term of: 1^2 + (1^2+2^2) + (1^2+2^2+3^2)+.....

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  1. Yahoo!
    • 3 years ago
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    \[an = \frac{ n(n+1)(2n+1) }{ 6 }\]

  2. koli123able
    • 3 years ago
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    how??

  3. SithsAndGiggles
    • 3 years ago
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    Do you see how the nth term is something like \[1^2+2^2+\cdots+(n-1)^2+n^2?\] What's the sum of all square numbers from 1 to n? i.e., \[\sum_{k=1}^n k^2?\]

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