At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\[\lim_{n \rightarrow \infty} n \sin (2pien!)\]

sry compute equation above using e^1

Is the expression
n.sin(2.pi.e.n!) ?

...which can't be right. What exactly are we taking the limit of?

the first thing you said

we're taking the limit of n sin i think

i'll use wolfram

http://www.math.utah.edu/ugrad/calc_challenge/calc-challenge-2006.pdf it's number 6

I see. Ok, let me think.

@mathaddict: the equation must be e^x , right? to apply Maclaurin series, how can you apply to e^1

got it

This is very counter-intuitive result. Adding this to the the archives.

Better to post the question and then mail me with the link.

how to post the link. once , other asked me to do that but I didn't know how to send the link

Just copy it from your browser and paste it into a message

ok, let me try once

Hm, possibly. I'm not sure.