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P.nut1996

  • 3 years ago

y varies directly as the square of x. When x = 3, y = 18. What is the value of y when x = 4? A.12 B. 16 C. 24 D. 32

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  1. ghass1978
    • 3 years ago
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    y1/x1^2=y2/x2^2 => 18/9=y/16

  2. P.nut1996
    • 3 years ago
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    ?

  3. ghass1978
    • 3 years ago
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    solve for y

  4. P.nut1996
    • 3 years ago
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    2=y/16

  5. P.nut1996
    • 3 years ago
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    ?

  6. ghass1978
    • 3 years ago
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    so y=16*2=32

  7. P.nut1996
    • 3 years ago
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    Thanks!

  8. ghass1978
    • 3 years ago
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    np

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