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- anonymous

Write the equation of the parabola in vertex form.
A.
y = (x + 1)2 + 3
B.
y = (x + 1)2 – 3
C.
y = (x – 1)2 – 3
D.
y = (x – 1)2 + 3

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- anonymous

- chestercat

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- anonymous

thats the wrong graph

- ZeHanz

Do you see the zeroes at -1 and 4?
The vertex is right in the middle of them: x = 1½.
Also the y-coordinate of the vertex seems to be 7½.
I cannot match it...

- anonymous

hold on let me get the other one

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- ZeHanz

Thought so... ;)

- anonymous

- anonymous

there

- ZeHanz

What are the coordinates of the vertex?

- anonymous

um, (1,3)

- anonymous

?

- ZeHanz

No, you have to go to the left and down... I get (-1, -3).

- anonymous

oh okay

- ZeHanz

So if you look at the answer options, that doesn't help much: these same numbers are in every option, sometimes + sometimes -...
You can find the right one by comparing this graph with that of the "father of all parabolas": y = x². That one has a vertex in (0, 0).
So if x = 0, you get the other coodrinate of the vertex (also 0).
In your parabola, you have to set x = -1 to get the vertex, so you get (x+1)² in the formula.

- anonymous

(x+1)^2+3

- ZeHanz

That would be all, if the y-coordinate of the vertex was at y = 0,
just as the vertex of y = x².
But this isn't the case, it lies 3 units lower!
OK, just subtract 3 from the formula, result: y = (x+1)²-3

- ZeHanz

You added 3, which would make the parabola go 3 units up, instead of down...

- anonymous

okay, thank so much for all your help :D

- ZeHanz

YW! Hope you understand the principle of moving the parabola.

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