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Dodo1

  • 3 years ago

limit comupting limit using the limit law

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  1. Dodo1
    • 3 years ago
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    \[\lim_{x \rightarrow 1} \frac{ x^4+x^3-2x }{ }\]

  2. Dodo1
    • 3 years ago
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    not working so Lim x^4+x^3-2x/x^5+2x-3 x->1

  3. ZeHanz
    • 3 years ago
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    Do you mean l'Hôpital's Rule by limit law? In that case take the derivative of both the numerator and the denominator and then take the limit as x goes to 1.

  4. Dodo1
    • 3 years ago
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    yes!

  5. Dodo1
    • 3 years ago
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    I thought I need to factorize first

  6. ZeHanz
    • 3 years ago
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    That can help sometimes, but factorising the denominator is difficult and l'H will crack it anyway...

  7. Dodo1
    • 3 years ago
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    Whats I`H?

  8. Dodo1
    • 3 years ago
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    I have to go meeting but I will back later. thanks,

  9. ZeHanz
    • 3 years ago
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    l'H = l'Hôpital's Rule

  10. Dodo1
    • 3 years ago
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    Do i plug numbers into the equation>?

  11. LABurn
    • 3 years ago
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    No, using l'Hôpital's Rule allows you to take the limit as x goes to 1 of the top and bottom separately.

  12. ZeHanz
    • 3 years ago
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    So, after differentiating separately yo now have this:\[\lim_{x \rightarrow 1}\frac{ 4x^3+3x^2-2 }{ 5x^4+2 }\]No 0/0 problem anymore, just set x=1 to see the result.

  13. Dodo1
    • 3 years ago
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    Ok thank you!

  14. ZeHanz
    • 3 years ago
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    YW!

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