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raebaby420
Group Title
Use the elimination method to solve the following system of equations.
4x – 2y – z = –5
x – 3y + 2z = 3
3x + y – 2z = –5
 one year ago
 one year ago
raebaby420 Group Title
Use the elimination method to solve the following system of equations. 4x – 2y – z = –5 x – 3y + 2z = 3 3x + y – 2z = –5
 one year ago
 one year ago

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texaschic101 Group TitleBest ResponseYou've already chosen the best response.2
4x  2y  z = 5 x  3y + 2z = 3 >(4)  4x  2y  z =  5 (result of multiplying by 4) 4x + 12y  8z =  12 add first two equations 10y  9z =  17 x  3y + 2z = 3 >(3) 3x + y  2z =  5  3x + 9y  6z =  9 (result of multiplying by 3) 3x + y  2z =  5 add last two equations 10y  8z =  14 now add the answers of both sets of equations... 10y  9z =  17 >(1) 10y  8z =  14  10y + 9z = 17 (result of multiplying by 1) 10y  8z =  14 add z = 3 Now sub 3 in for z in either of the above equations... 10y  8z =  14 10y  8(3) =  14 10y  24 =  14 10y =  14 + 24 10y = 10 y = 1 now sub 1 in for y and 3 in for z in any of the first 3 equations 4x  2y  z =  5 4x  2(1)  3 =  5 4x  2  3 =  5 4x =  5 + 5 4x = 0 x = 0 Now sub all 3 known variables into any of the first 3 equations to check your answers... x  3y + 2z = 3 0  3(1) + 2(3) = 3 3 + 6 = 3 3 = 3 (correct) ANSWER : (0,1,3) < x = 0, y = 1, z = 3 :)
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much for putting your time into helping me!
 one year ago

texaschic101 Group TitleBest ResponseYou've already chosen the best response.2
Not a problem...thats what I am here for :)
 one year ago
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