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 one year ago
Use the elimination method to solve the following system of equations.
4x – 2y – z = –5
x – 3y + 2z = 3
3x + y – 2z = –5
 one year ago
Use the elimination method to solve the following system of equations. 4x – 2y – z = –5 x – 3y + 2z = 3 3x + y – 2z = –5

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texaschic101
 one year ago
Best ResponseYou've already chosen the best response.24x  2y  z = 5 x  3y + 2z = 3 >(4)  4x  2y  z =  5 (result of multiplying by 4) 4x + 12y  8z =  12 add first two equations 10y  9z =  17 x  3y + 2z = 3 >(3) 3x + y  2z =  5  3x + 9y  6z =  9 (result of multiplying by 3) 3x + y  2z =  5 add last two equations 10y  8z =  14 now add the answers of both sets of equations... 10y  9z =  17 >(1) 10y  8z =  14  10y + 9z = 17 (result of multiplying by 1) 10y  8z =  14 add z = 3 Now sub 3 in for z in either of the above equations... 10y  8z =  14 10y  8(3) =  14 10y  24 =  14 10y =  14 + 24 10y = 10 y = 1 now sub 1 in for y and 3 in for z in any of the first 3 equations 4x  2y  z =  5 4x  2(1)  3 =  5 4x  2  3 =  5 4x =  5 + 5 4x = 0 x = 0 Now sub all 3 known variables into any of the first 3 equations to check your answers... x  3y + 2z = 3 0  3(1) + 2(3) = 3 3 + 6 = 3 3 = 3 (correct) ANSWER : (0,1,3) < x = 0, y = 1, z = 3 :)

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much for putting your time into helping me!

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2Not a problem...thats what I am here for :)
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