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gjhfdfg
 one year ago
Best ResponseYou've already chosen the best response.0I have a question that wants me to use the leading coefficient test to determine the end behavior of f(x) = x^2(x + 2)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1expand the product to a bunch of terms that are added together

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1then forget the stuff after the first term; the end behaviours of the function act in the same manner as the leading term

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360618376605:dw the end behaviours of both sketches is the same .... they both behave like x^2

gjhfdfg
 one year ago
Best ResponseYou've already chosen the best response.0I mean what did you mean by expand the product to abunch of terms added together ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1what does: x^2(x + 2) look like after you multiply the x^2 into the (x+2) ??

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1close: x^2(x+2) = x^3 + 2x^2 now, end behaviour is what the graph acts like for values of x that go way off to the left or right zero. would you agree that the 2x^2 term contributes very little to the equation for say x=1000000000000 ?? if so, then the end bahviours (the behaviour of large values of x) gets dominated by the first term

gjhfdfg
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure, I wouldnt think so?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the leading term of a polynomial always takes control for larger values of x. so we can know what the end behaviour of a graph of any given polynomial is by just comparing it to the standard graph of its leading term. How do the ends of x^3 behave?

gjhfdfg
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea, I don't get any this.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1you need to be able to know a few basic graph shapes :/ dw:1360619317867:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1since the leading term of the expanded product is x^3; the ends will act in the same manner is x^3 .... another thing to keep in mind is that all even powers act alike; and all odd powers act aloike

gjhfdfg
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for trying to explain this to me, I think Im just gonna have to find me a tutor. Problems like this is foreign language to me, very hard to under stand.
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