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haleyking345

  • 3 years ago

Solve the equation: a.) 2 cos^2x-cos x=1

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  1. Marx
    • 3 years ago
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    let's define \[t:= \cos(x)\] we have the quadratic equation: \[2t^2-t=1\] can you find it's solutions?

  2. haleyking345
    • 3 years ago
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    Would it be cos=1? Which means cos=0 degrees or 360 degrees?

  3. Marx
    • 3 years ago
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    there are two solutions, \[\cos(x)=1\] and \[\cos(x)=-\frac{1}{2}\] so x can be either \[360^\circ{} k\] (for every integer k) or \[120^\circ{}+ 360^{\circ}k\] or \[240^\circ{}+ 360^{\circ}k\]

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