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Finding x intercepts for quadratic functions

Mathematics
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I need help on finding the x intercept on this quadratic function, |dw:1360627184057:dw|
do you know the formula? http://en.wikipedia.org/wiki/Quadratic_equation#Quadratic_formula
I do now I think,

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Other answers:

Hold on,
Ok, so I solve it like this? |dw:1360627636615:dw|
almost, a= 6 not 6x^2
that way you have a number :D
What happens to the x^2?
well: a,b and c are the coefficients so there's no need for x's. check the formula again. so you should have two solutions.
Them 2 solutions got me lost..
|dw:1360628346901:dw|
I got that so far,
it goes like this: \[x_{1,2} =\frac{-12\pm \sqrt{12^2-4\cdot 6 \cdot 5}}{6\cdot 2} = -1\pm \frac{\sqrt{24}}{12}=-1\pm\frac{2\sqrt{6}}{12}=-1\pm\frac{1}{\sqrt6}\] so we have : \[x_1 = 1+\frac{1}{\sqrt{6}}\] and x_2 = 1-\frac{1}{\sqrt{6}}
i mean \[x_2= 1-\frac{1}{\sqrt{6}}\]
ahem, yeah with -1 ... :)
How did you get the\[\sqrt{24}\] ?
\[12^2 - 4\cdot 6 \cdot 5 = 144 - 120 = 24\]
Ah, ok I was thinking 12*12 = 120 instead of 144. My bad,
But then how did \[2\sqrt{6}\] come in?
The square roots throw me off...
\[\sqrt{24}=\sqrt{4\cdot 6} =\sqrt{4} \cdot \sqrt{6} = 2\sqrt{6}\]
Ah ok got it thanks.!
you welcome :)
Do we do anything else to it?
what do you mean?
Is there anything else I should do to the answer(s)? None of them match my answer choices
hmm what are your choices?
1 Attachment
so it's the second one: \[\frac{-6\pm \sqrt{6}}{6}\] it's basically what I told you but in a different form
Ah ok thank you
\[\frac{-6\pm\sqrt{6}}{6} = -1 \pm \frac{\sqrt{6}}{6} = -1\pm \frac{1}{\sqrt{6}}\]
Got it.!

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