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gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I need help on finding the x intercept on this quadratic function, dw:1360627184057:dw
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
do you know the formula? http://en.wikipedia.org/wiki/Quadratic_equation#Quadratic_formula
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I do now I think,
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Ok, so I solve it like this? dw:1360627636615:dw
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
almost, a= 6 not 6x^2
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
that way you have a number :D
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
What happens to the x^2?
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
well: a,b and c are the coefficients so there's no need for x's. check the formula again. so you should have two solutions.
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Them 2 solutions got me lost..
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
dw:1360628346901:dw
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I got that so far,
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
it goes like this: \[x_{1,2} =\frac{12\pm \sqrt{12^24\cdot 6 \cdot 5}}{6\cdot 2} = 1\pm \frac{\sqrt{24}}{12}=1\pm\frac{2\sqrt{6}}{12}=1\pm\frac{1}{\sqrt6}\] so we have : \[x_1 = 1+\frac{1}{\sqrt{6}}\] and x_2 = 1\frac{1}{\sqrt{6}}
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
i mean \[x_2= 1\frac{1}{\sqrt{6}}\]
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
ahem, yeah with 1 ... :)
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
How did you get the\[\sqrt{24}\] ?
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
\[12^2  4\cdot 6 \cdot 5 = 144  120 = 24\]
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Ah, ok I was thinking 12*12 = 120 instead of 144. My bad,
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
But then how did \[2\sqrt{6}\] come in?
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
The square roots throw me off...
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
\[\sqrt{24}=\sqrt{4\cdot 6} =\sqrt{4} \cdot \sqrt{6} = 2\sqrt{6}\]
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Ah ok got it thanks.!
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
you welcome :)
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Do we do anything else to it?
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
what do you mean?
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Is there anything else I should do to the answer(s)? None of them match my answer choices
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
hmm what are your choices?
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
so it's the second one: \[\frac{6\pm \sqrt{6}}{6}\] it's basically what I told you but in a different form
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Ah ok thank you
 one year ago

Marx Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{6\pm\sqrt{6}}{6} = 1 \pm \frac{\sqrt{6}}{6} = 1\pm \frac{1}{\sqrt{6}}\]
 one year ago
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