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jazy

  • 3 years ago

Quadratic Equations

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  1. jazy
    • 3 years ago
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    |dw:1360629073240:dw|

  2. jazy
    • 3 years ago
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    Quadratic equation: \[\huge x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

  3. jazy
    • 3 years ago
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    Substitute the values: \[\huge x = \frac{ -(12) \pm \sqrt{(12)^2 - 4(6)(5)} }{ 2(6) }\]

  4. jazy
    • 3 years ago
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    Simplify it: \[\huge x = \frac{ -12 \pm \sqrt{144 - 120} }{ 12} \]

  5. jazy
    • 3 years ago
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    Keep simplifying: \[\huge x = \frac{ -12 \pm \sqrt{24} }{ 12} \] Use a calculator and find the Square root of 24. This one is very useful: http://web2.0calc.com/ \[ x = \frac{ -12 \pm 4.898 9 }{ 12} \]

  6. jazy
    • 3 years ago
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    Now we have two solutions to find: \[x = \frac{ -12 + 4.8989 }{ 12} \quad and \quad x = \frac{ -12 - 4.8989 }{ 12 }\]

  7. jazy
    • 3 years ago
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    Let's do the first one... \[x = \frac{ -12 + 4.8989 }{ 12} = \frac{ -7.1011 }{ 12 } = -0.5917 \] Round it.

  8. jazy
    • 3 years ago
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    Now the other... \[x = \frac{ -12 - 4.8989 }{ 12 } = \frac{ -16.8989 }{ 12 } = -1.4082 \] Round it.

  9. jazy
    • 3 years ago
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    So you have: x = -0.5917 x = -1.4082 Of course, you might need to round them a bit more.

  10. jazy
    • 3 years ago
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    Does this help @gjhfdfg ?

  11. gjhfdfg
    • 3 years ago
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    It helps a little more, how would I put that into fraction form?

  12. jazy
    • 3 years ago
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    What are your answer choices?

  13. gjhfdfg
    • 3 years ago
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