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jazyBest ResponseYou've already chosen the best response.0
Quadratic equation: \[\huge x = \frac{ b \pm \sqrt{b^2  4ac} }{ 2a }\]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Substitute the values: \[\huge x = \frac{ (12) \pm \sqrt{(12)^2  4(6)(5)} }{ 2(6) }\]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Simplify it: \[\huge x = \frac{ 12 \pm \sqrt{144  120} }{ 12} \]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Keep simplifying: \[\huge x = \frac{ 12 \pm \sqrt{24} }{ 12} \] Use a calculator and find the Square root of 24. This one is very useful: http://web2.0calc.com/ \[ x = \frac{ 12 \pm 4.898 9 }{ 12} \]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Now we have two solutions to find: \[x = \frac{ 12 + 4.8989 }{ 12} \quad and \quad x = \frac{ 12  4.8989 }{ 12 }\]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Let's do the first one... \[x = \frac{ 12 + 4.8989 }{ 12} = \frac{ 7.1011 }{ 12 } = 0.5917 \] Round it.
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Now the other... \[x = \frac{ 12  4.8989 }{ 12 } = \frac{ 16.8989 }{ 12 } = 1.4082 \] Round it.
 one year ago

jazyBest ResponseYou've already chosen the best response.0
So you have: x = 0.5917 x = 1.4082 Of course, you might need to round them a bit more.
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Does this help @gjhfdfg ?
 one year ago

gjhfdfgBest ResponseYou've already chosen the best response.0
It helps a little more, how would I put that into fraction form?
 one year ago

jazyBest ResponseYou've already chosen the best response.0
What are your answer choices?
 one year ago
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