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Quadratic Equations

Mathematics
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|dw:1360629073240:dw|
Quadratic equation: \[\huge x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
Substitute the values: \[\huge x = \frac{ -(12) \pm \sqrt{(12)^2 - 4(6)(5)} }{ 2(6) }\]

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Other answers:

Simplify it: \[\huge x = \frac{ -12 \pm \sqrt{144 - 120} }{ 12} \]
Keep simplifying: \[\huge x = \frac{ -12 \pm \sqrt{24} }{ 12} \] Use a calculator and find the Square root of 24. This one is very useful: http://web2.0calc.com/ \[ x = \frac{ -12 \pm 4.898‚ÄČ9 }{ 12} \]
Now we have two solutions to find: \[x = \frac{ -12 + 4.8989 }{ 12} \quad and \quad x = \frac{ -12 - 4.8989 }{ 12 }\]
Let's do the first one... \[x = \frac{ -12 + 4.8989 }{ 12} = \frac{ -7.1011 }{ 12 } = -0.5917 \] Round it.
Now the other... \[x = \frac{ -12 - 4.8989 }{ 12 } = \frac{ -16.8989 }{ 12 } = -1.4082 \] Round it.
So you have: x = -0.5917 x = -1.4082 Of course, you might need to round them a bit more.
Does this help @gjhfdfg ?
It helps a little more, how would I put that into fraction form?
What are your answer choices?
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