jazy Group Title Quadratic Equations one year ago one year ago

1. jazy

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2. jazy

Quadratic equation: $\huge x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }$

3. jazy

Substitute the values: $\huge x = \frac{ -(12) \pm \sqrt{(12)^2 - 4(6)(5)} }{ 2(6) }$

4. jazy

Simplify it: $\huge x = \frac{ -12 \pm \sqrt{144 - 120} }{ 12}$

5. jazy

Keep simplifying: $\huge x = \frac{ -12 \pm \sqrt{24} }{ 12}$ Use a calculator and find the Square root of 24. This one is very useful: http://web2.0calc.com/ $x = \frac{ -12 \pm 4.898 9 }{ 12}$

6. jazy

Now we have two solutions to find: $x = \frac{ -12 + 4.8989 }{ 12} \quad and \quad x = \frac{ -12 - 4.8989 }{ 12 }$

7. jazy

Let's do the first one... $x = \frac{ -12 + 4.8989 }{ 12} = \frac{ -7.1011 }{ 12 } = -0.5917$ Round it.

8. jazy

Now the other... $x = \frac{ -12 - 4.8989 }{ 12 } = \frac{ -16.8989 }{ 12 } = -1.4082$ Round it.

9. jazy

So you have: x = -0.5917 x = -1.4082 Of course, you might need to round them a bit more.

10. jazy

Does this help @gjhfdfg ?

11. gjhfdfg

It helps a little more, how would I put that into fraction form?

12. jazy