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JaySongChang
 2 years ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.)
Lim
x>(pi/2)+ 7e^(tan x)
JaySongChang
 2 years ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.) Lim x>(pi/2)+ 7e^(tan x)

This Question is Closed

JaySongChang
 2 years ago
Best ResponseYou've already chosen the best response.0I thought it would be infinity but apparently infinity is incorrect

azolotor
 2 years ago
Best ResponseYou've already chosen the best response.0\[\tan(\pi /2) = \sin(\pi /2)/\cos(\pi /2) = 1/\cos(\pi /2)\] Now you can take the left and right hand limits of this to find out if they are equal. In this case they are not so the limit does not exist.

JaySongChang
 2 years ago
Best ResponseYou've already chosen the best response.0The answer does not exist is marked incorrectly for this problem.

JaySongChang
 2 years ago
Best ResponseYou've already chosen the best response.0I graphed the 7e^(tan x) and it appears that as X approaches pi/2 the graph goes to infinity

azolotor
 2 years ago
Best ResponseYou've already chosen the best response.0Only from the right. From the left it approaches 7

JaySongChang
 2 years ago
Best ResponseYou've already chosen the best response.0I think the question is only asking for the right hand limit

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1from right its 0, from left its infinity.

JaySongChang
 2 years ago
Best ResponseYou've already chosen the best response.0since there is a small + sign the left of the Pi/2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1see, from right means x > pi/2 x is in 2nd quadrant where tan x is negative. also, tan pi/2 = infinity so, e^{infinity} will tend to 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1from left means x< pi/2 x is in 1st quadrant where tan x is positive. also, tan pi/2 = infinity so, e^{infinity} will tend to infinity
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